Answer:
(I suppose that we want to find the probability of first randomly drawing a red checker and after that randomly drawing a black checker)
We know that we have:
12 red checkers
12 black checkers.
A total of 24 checkers.
All of them are in a bag, and all of them have the same probability of being drawn.
Then the probability of randomly drawing a red checkers is equal to the quotient between the number of red checkers (12) and the total number of checkers (24)
p = 12/24 = 1/2
And the probability of now drawing a black checkers is calculated in the same way, as the quotient between the number of black checkers (12) and the total number of checkers (23 this time, because we have already drawn one)
q = 12/23
The joint probability is equal to the product between the two individual probabilities:
P = p*q = (1/2)*(12/23) = 0.261
T
24 students / 3 groups = 8
8 parents will be needed to put the students into groups of 3.
Answer: x = 2 degrees Fahrenheit
Step-by-step explanation:
5-3= 2 it’s a pretty simple equation
First you take 15 and divide it by 5. That leaves you with 3. You also need to decide the x’s so you subtract the exponents (2-3=-1)
so you now have (y^10z^7)/(y^4z^10)3x^-1
Next we will divide the y’s.
Again, subtract the exponents (10-4=6) to get y^6
Now we have (3x^-1)(y^6) (z^7/z^10)
Last is z, we subtract the exponents again (7-10=-3) and get z^-3
Our answer is (3x^-1)(y^6)(z^-3)
