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4 years ago

Is the square root of 16.45 a rational number or irrational number?

Mathematics

2 answers:

Amiraneli [1.4K]4 years ago

7 0

Answer:

irrational

Step-by-step explanation:

4.05585995813

does not terminate or repeat

not an integer

trapecia [35]4 years ago

3 0

Answer:

Irrational

Step-by-step explanation:

The square root of 16.45 would be a number that will never end, making it irrational.

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Please help me with this equation in mathematics

nignag [31]

Answer:

<em><u>Osksjsnnsjdndnjxmxmdmsmskskmsoxkzmxz</u></em>

6 0

3 years ago

What is the area of the green shaded part?

Mandarinka [93]

Answer:

$7.74 \: {cm}^{2}$

Step-by-step explanation:

Area of the green shaded part

= Area of square with side 6 cm - Area of circle with radius (6/2=3) 3 cm.

$= {side}^{2} - \pi {r}^{2} \\ = {6}^{2} - 3.14 \times {3}^{2} \\ = 36 - 28.26 \\ = 7.74 \: {cm}^{2}$

8 0

3 years ago

One 16-oz can of vegetable soup cost $1.78. Two pints of vegetable soup cost $3.17. Which option is the better deal?

aleksklad [387]

One 16 oz can of veggie soup cost $ 1.78......1.78/16 = 0.11 per oz

1 pint = 16 oz......so 2 pints = (2 * 16) = 32 oz

so 32 oz ( or 2 pints) of veggie soup cost $ 3.17.....3.17/32 = 0.10 per oz

so the better deal (the cheapest one) is the 2 pints for $ 3.17

8 0

3 years ago

Evaluate t-u/v when t=2 u=(-8) v(-1/2)

Dovator [93]

Simple, plug n chug...

$t- \frac{u}{v}$

t=2

u=-8

v=-0.5

Now, plug in what you have,

$2- \frac{-8}{-0.5}$

$\frac{-8}{-0.5} =16$

Now,

2-16=-14

Thus, your answer, -14.

5 0

3 years ago

Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal

lisabon 2012 [21]

Given the following functions below,

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}$

Factorising the denominators of both functions,

Factorising the denominator of f(x),

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}$

Factorising the denominator of g(x),

$\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}$

Multiplying both functions,

$undefined$

4 0

1 year ago