Explanation:
We should have an invariant point condition (The degree of freedom F=0 as per phase rule) for a quadruple point to occur and to test whether this argument is valid or not we must implement phase rule in a given case.
So, as per the Phase Principle F= C-P+2 Here in this situation all types are allotropic implying they consist of the same chemical compound, i.e. each have the same chemical composition.
Then constituents C=1, P= 4 (because they have 4 phases) Also no parameters for the given system are 2, Pressure and Temperature, these are found by including 2 in the formula of phase rule
Therefore, F= 1-4+ 2=-1 is certainly not equal to 0 and therefore the claim that they found a quadruple point is counterfeit.
The freezing point depression is a colligative property which means that it is proportional to the number of particles dissolved.
The number of particles dissolved depends on the dissociation constant of the solutes, when theyt are ionic substances.
If you have equal concentrations of two solutions on of which is of a ionic compound and the other not, then the ionic soluton will contain more particles (ions) and so its freezing point will decrease more (will be lower at end).
In this way you can compare the freezing points of solutions of KCl, Ch3OH, Ba(OH)2, and CH3COOH, which have the same concentration.
As I explained the solution that produces more ions will exhibit the greates depression of the freezing point, leading to the lowest freezing point.
In this case, Ba(OH)2 will produce 3 iones, while KCl will produce 2, CH3OH will not dissociate into ions, and CH3COOH will have a low dissociation constant.
Answer: Then, you can predict that Ba(OH)2 solution has the lowest freezing point.
Answer:
they use* them to defrost food, to cook food, and to boil liquid
Explanation: