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3 years ago

6

How many molecules of SO2 are in 2.45 g of SO2? (molar mass=64.06 g/mol). (Hint: you need to use your entire stoichiometry flow

chart!)
0.0382 molecules

9.45 x10^25 molecules

2.30 x 10^22 molecules

6.35 x 10^-26 molecules

1 answer:

Reil [10]3 years ago

8 0

9.45 x10^25 molecules

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What's does variables mean

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Factor that can be controlled changed or measured in an experiment.

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Which feature is created on the exterior of a volcano when it erupts?

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Answer:

When the magma reaches it boiling point and it starts to rise

Explanation:

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3 years ago

Which has a higher concentration of water molecules— 200 molecules of water, or a mixture of 300 molecules of water and 100 mole

Dovator [93]

<h3>Answer:</h3>

200 molecules of water has the highest concentration.

<h3>Explanation:</h3>

In chemistry, Concentration is defined as the amount of substance divided by the total volume of the constituents making the mixture.

<u>Case 1:</u> 200 Molecules of Water:

In this case we are having system which is made up of 200 purely water molecules and there is no other substance present in the system. Hence, for ease we can write it as,

Concentration = Molecules of Water ÷ Total Molecules of Mixture

Concentration = 200 ÷ 200

Concentration = 1

<u>Case 2:</u> 300 Molecules of Water and 100 Molecules of Food Coloring:

In this case we are having a mixture which is made up of 300 water molecules and 200 food coloring molecules. Hence, we can write it as,

Concentration = Molecules of Water ÷ Total Molecules of Mixture

Concentration = 300 ÷ (300 + 200)

Concentration = 300 ÷ 500

Concentration = 0.6

Therefore, it is proved that the concentration of pure 200 molecules of water is greater.

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4 years ago

What mass of carbon monooxide must be burned to produce 175 kJ of heat under standard state condaitions?

Sphinxa [80]

Answer:

17.3124 grams

Explanation:

Given;

Amount of heat to be produced = 175 kJ

Molar mass of the carbon monoxide = 12 + 16 = 28 grams

Now,

The standard molar enthalpy of carbon monoxide = 283 kJ/mol

Thus,

To produce 175 kJ heat, number of moles of CO required will be

= Amount heat to be produced / standard molar enthalpy of CO

or

= 175 / 283

= 0.6183

Also,

number of moles = Mass / Molar mass

therefore,

0.6183 = Mass / 28

or

Mass of the CO required = 0.6183 × 28 = 17.3124 grams

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4 years ago

What is the percent yield for carbon dioxide if 10.0 grams of carbon

ivolga24 [154]

The percent yield : 81.5%

<h3>Further explanation</h3>

Percent yield is the compare of the amount of product obtained from a reaction with the amount you calculated

General formula:

Percent yield = (Actual yield / theoretical yield )x 100%

An actual yield is the amount of product actually produced by the reaction. A theoretical yield is the amount of product that you calculate from the reaction equation according to the product and reactant coefficients

Reaction

2CO+O₂⇒2CO₂

mol CO(MW=28,01 g/mol)

$\tt \dfrac{10}{28.01}=0.357$

mass CO₂ (theoretical)(MW=44,01 g/mol)

$\tt 0.357\times 44.01=15.712~g$

the percent yield :

$\tt \dfrac{12.81}{15.712}\times 100\%=81.5\%$

3 0

3 years ago