Log (10-4x) = log (10-3x)

Mathematics

2 answers:

oksano4ka [1.4K]3 years ago

8 0

$\log (10-4x) = \log (10-3x) \\
D:10-4x>0 \wedge 10-3x>0\\
D:4x$

AleksandrR [38]3 years ago

4 0

$D:\\10-4x > 0\ \wedge\ 10-3x > 0\\-4x > -10\ \vee\ -3x > -10\\\\x < \frac{10}{4}\ \wedge\ x < \frac{10}{3}\\\\x < 2\frac{1}{2}\ \wedge\ x < 3\frac{1}{3}\\\\x\in(-\infty;\ 2\frac{1}{2})$

$log(10-4x)=log(10-3x)\iff10-4x=10-3x\\\\-4x+3x=10-10\\\\-x=0\ \ \ /\cdot(-1)\\\\x=0\in D\\\\Solution:x=0$

You might be interested in

Simplify (7x)- (-2x). A 5x B-5x C9x D-9x

WITCHER [35]

You answer is C because 7-(-2) is 9 and then u just had an X at the end .

Hope this helps:)

6 0

3 years ago

Read 2 more answers

Someone please help me

arlik [135]

Answer:

Step-by-step explanation:

25% of x = 0.25

12/0.25 = 48

4 0

3 years ago

Cassie has a small cube shaped box. Its volume is 64 cubic cm. What is the area of one face of tje box.

Andrews [41]

Answer: One face is 16 square centimeters.

Step-by-step explanation: To find the area of a face, you need to know the length of the side. All the sides of the cube are the same, so take the cube root of 64.

$\sqrt[3]{64}=4$ cm is the length of the side

The area of one face is the side length squared 4² = 16

4cm × 4cm = 16 square centimeters.

8 0

3 years ago

The Capulet and Montague families love writing. Last year, each Capulet wrote 44 essays, each Montague wrote 66 essays, and both

makvit [3.9K]

Answer: The answer is 2275 and 0.

Step-by-step explanation: Given that the Capulet and Montague families love to write. Last year, each Capulet wrote 44 essays, each Montague wrote 66 essays and both families wrote 100100 essays in total. This year, each Capulet wrote 88 essays, each Montague wrote 1212 essays, and both families wrote 200200 essays in total. We are to find the number of Capulets members and Montagues members.

Let there are 'x' members in Capulet family and 'y' members in the Montague family. Then, we have

$44x+66y=100100,\\\\88x+1212y=200200.$