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andrew11 [14]
3 years ago
13

Simplify (7x)- (-2x). A 5x B-5x C9x D-9x

Mathematics
2 answers:
Scrat [10]3 years ago
7 0

Answer:  The correct option is

(C) 9x.

Step-by-step explanation:  We are given to simplify the following expression :

E=(7x)-(-2x)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

We will be using the following rule in simplifying the given expression :

a-(-b)=a+b.

From expression (i), we get

E\\\\=(7x)-(-2x)\\\\=7x+2x\\\\=(7+2)x\\\\=9x.

Thus, the required simplified form is 9x.

Option (C) is CORRECT.

WITCHER [35]3 years ago
6 0
You answer is C because 7-(-2) is 9 and then u just had an X at the end .

Hope this helps:)
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Answer:

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Step-by-step explanation:

first find -\sqrt{5}\\

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now round it to match the lenth of the other problem

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now remember that the bigger the negitive number, the smaller it really is,

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-1.96312>-2.2360

7 0
2 years ago
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The probability that a randomly selected 2 2​-year-old male garter snake garter snake will live to be 3 3 years old is 0.98861 0
Mnenie [13.5K]

Answer:

a. Probability = 0.97735

b. Probability = 0.92294

c. P(At\ Least\ One) = 1

No, it is not unusual if at least 1 lives up to 3.

Step-by-step explanation:

Given

Represent the probability that a 2 year old snake will live to 3 with P(Live);

P(Live) = 0.98861

Solving (a): Probability that two selected will live to 3 years.

Both snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)\ and\ P(Live)

Probability = 0.98861 * 0.98861

Probability = 0.9773497321

Probability = 0.97735 <em>--- Approximated</em>

Solving (b): Probability that seven selected will live to 3 years.

All 7 snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)^n

Where n = 7

Probability = 0.98861^7

Probability = 0.92294324145

Probability = 0.92294 <em>--- Approximated</em>

Solving (c): Probability that at least one of seven selected will not live to 3 years.

In probabilities, the following relationship exist:

P(At\ Least\ One) = 1 - P(None).

So, first we need to calculate the probability that none of the 7 lived up to 3.

If the probability that one lived up to 3 years is 0.98861, then the probability than one do not live up to 3 years is 1 - 0.98861

This gives:

P(Not\ Live) = 0.01139

The probability that none of the 7 lives up to 3 is:

P(None) = P(Not\ Live)^7

P(None) = 0.01139^7

Substitute this value for P(None) in

P(At\ Least\ One) = 1 - P(None).

P(At\ Least\ One) = 1 - 0.01139^7

P(At\ Least\ One) = 0.99999999999997513055642436060443621

P(At\ Least\ One) = 1 ---- Approximated

No, it is not unusual if at least 1 lives up to 3.

This is so because the above results, which is 1 shows that it is very likely for at least one of the seven to live up to 3 years

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5 0
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