Answer:
Option A. one rectangle and two triangles
Option E. one triangle and one trapezoid
Step-by-step explanation:
step 1
we know that
The area of the polygon can be decomposed into one rectangle and two triangles
see the attached figure N 1
therefore
Te area of the composite figure is equal to the area of one rectangle plus the area of two triangles
so
![A=(8)(4)+2[\frac{1}{2}((8)(4)]=32+32=64\ yd^2](https://tex.z-dn.net/?f=A%3D%288%29%284%29%2B2%5B%5Cfrac%7B1%7D%7B2%7D%28%288%29%284%29%5D%3D32%2B32%3D64%5C%20yd%5E2)
step 2
we know that
The area of the polygon can be decomposed into one triangle and one trapezoid
see the attached figure N 2
therefore
Te area of the composite figure is equal to the area of one triangle plus the area of one trapezoid
so

I did number 6 to give you an idea of what you have to do. First find simplify the top and bottom and reduce!
Hope it helps! Comment if you have any questions!
50.74
B/c 43*.18=7.74
7.74+43=50.74
hope this helps
Answer:
Perimeter of a triangle = add all sides
Both the legs of the isosceles triangle are always EQUAL.
x+4x-6+4x-6 = 60
9x-12 = 60
9x = 60+12
9x = 72
x = 8
Answer:
-8, -7
Step-by-step explanation:
f(x)=x^2+15x+56
0 =x^2+15x+56
What two numbers multiply together to make 56 and add together to 15
7*8 = 56
7+8=15
0 = (x+8) (x+7)
Then use the zero product property
x+8 =0 x+7 =0
x+8-8 =0-8 x+7-7 =0-7
x=-8 x=-7