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3 years ago

2 (×+1)=3×-1 how to solve for x?

Mathematics

1 answer:

hram777 [196]3 years ago

4 0

Hi. 2 (×+1)=3×-1 ; 2x+2= 3x-1 ;
2x-3x= -1-2 ; -x = -3 ; x=3. Hope this helps.

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I need help in these questions

Salsk061 [2.6K]

Answer:

see explanation

Step-by-step explanation:

All of these questions use the external angle theorem, that is

The external angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠3 = 43° + 22° = 65°

∠2 + 71 = 92 ( subtract 71 from both sides )

∠2 = 21°

90 + ∠4 = 123 ( subtract 90 from both sides )

∠4 = 33°

2x - 15 + x - 5 = 148

3x - 20 = 148 ( add 20 to both sides )

3x = 168 ( divide both sides by 3 )

x = 56

Hence ∠ABC = x - 5 = 56 - 5 = 51°

2x + 27 + 2x - 11 = 100

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4x = 84 ( divide both sides by 4 )

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3 years ago

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Answer:

Step-by-step explanation:

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3 years ago

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maxonik [38]

Answer with Step-by-step explanation:

We are given that

$r(t)=< t^2,\frac{2}{3}t^3,t >$

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Now, substitute t=1

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$N(1)=\frac{}{\frac{2}{3}}=$

$N(1)=$

$B(1)=T(1)\times N(1)$

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$B(1)=i(\frac{-4}{9}-\frac{2}{9})-j(\frac{-4}{9}+\frac{1}{3})+k(\frac{4}{9}+\frac{2}{9})$

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$B(1)=\frac{1}{3}$

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