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Slav-nsk [51]
2 years ago
5

PLEASE HELP!!!! ASAP

Mathematics
1 answer:
tatiyna2 years ago
5 0

Answer:

78/5

Step-by-step explanation:

1/5 5x + 12 = 18

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3 years ago
What is the factorization of 121b4 − 49? (11b − 7)(11b − 7) (11b 7)(11b − 7) (11b2 − 7)(11b2 − 7) (11b2 7)(11b2 − 7)
Inessa05 [86]

The Factorization of 121b⁴ − 49 is (11b^2 + 7)(11b^2 - 7).

The equation 121b⁴ − 49

To find the Factorization of 121b⁴ − 49.

<h3>What is the factor of a^2-b^2?</h3>

The factor of a^2-b^2 is  (a+b)(a-b)

We have write the given equation in the form of a^2-b^2

= 121b^4 - 49\\= (11b^2)^2 - 7^2\\= (11b^2 + 7)(11b^2 - 7)

Therefore the factor of the 121b^4 − 49 is (11b^2 + 7)(11b^2 - 7).

To learn more about the factor visit:

brainly.com/question/25829061

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Who knows what 16+16 is? giving brainliest
vlada-n [284]

32 is the correct answer


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What is 83 + 119 + 17 =
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219

Step-by-step explanation:

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202 + 17 = 219

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