Is - 81526 rational

If you help with the correct answer u are a god .pt2

Brrunno [24]

a. Answer: D: (∞, ∞)

R: (-∞, ∞)

<u>Step-by-step explanation:</u>

Theoretical domain is the domain of the equation (without an understanding of what the x-variable represents).

Theoretical range is the range of the equation given the domain.

c(p) = 25p

There are no restrictions on the p so the theoretical domain is All Real Numbers.

Multiplying 25 by All Real Numbers results in the range being All Real Numbers.

a) D: (∞, ∞)

R: (-∞, ∞)

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b. Answer: D: (0, 200)

R: (0, 5000)

<u>Step-by-step explanation:</u>

Practical domain is the domain of the equation WITH an understanding of what the x-variable represents.

Practical range is the range of the equation given the practical values of the domain.

The problem states that p represents the number of cups. Since we can't have a negative amount of cups, p ≥ 0. The problem also states that Bonnie will purchase a maximum of 200 cups. So, 0 ≤ p ≤ 200

The range is 25p → (25)0 ≤ (25)p ≤ (25)200

→ 0 ≤ 25p ≤ 5000

b) D: (0, 200)

R: (0, 5000)

5 0

3 years ago

The line $y = 3$ intersects the graph of $y = 4x^2 + x - 1$ at the points $A$ and $B$. The distance between $A$ and $B$ can be w

raketka [301]

Answer:

61

Step-by-step explanation:

Let's find the points $A$ and $B$ .

We know that the $y$ -coordinates of both are $3$ .

So let's first solve:

$3=4x^2+x-1$

Subtract 3 on both sides:

$0=4x^2+x-1-3$

Simplify:

$0=4x^2+x-4$

I'm going to use the quadratic formula, $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ , to solve.

We must first compare to the quadratic equation, $ax^2+bx+c=0$ .

$a=4$

$b=1$

$c=-4$

$\frac{-1 \pm \sqrt{1^2-4(4)(-4)}}{2(4)}$

$\frac{-1 \pm \sqrt{1+64}}{8}$

$\frac{-1 \pm \sqrt{65}}{8}$

Since the distance between the points $A$ and $B$ is horizontal. We know this because they share the same $y-coordinate$ .This means we just need to find the positive difference between the $x$ -values we found for the points of $A$ and $B$ .

So that is, the distance between $A$ and $B$ is:

$\frac{-1+\sqrt{65}}{8}-\frac{-1-\sqrt{65}}{8}$

$\frac{-1+\sqrt{65}+1+\sqrt{65}}{8}$

$\frac{2\sqrt{65}}{8}$

$\frac{\sqrt{65}}{4}$

If we compare this to $\frac{\sqrt{m}}{n}$ , we should see that:

$m=65 \text{ and } n=4$ .

So $m-n=65-4=61$ .

5 0

2 years ago

Read 2 more answers

Why does a calculator return an error when trying to find inverse sine of 1.055?

Rashid [163]

The calculator returns an error as the answer for the inverse sine of 1.055 because the acceptable range for sine is only from 0 to 1.00 in which 1.055 is clearly greater than. This is also the same as for the cosine values.

5 0

2 years ago

Read 2 more answers

Find the area of the isosceles triangle. please help thanks

fiasKO [112]

Answer:

1080 m^2 Don't submit m^2 in your answer.

Step-by-step explanation:

Givens

The catch is to find h

To do that, use a^2 + b^2 = c^2

a b and c are in the same 1/2 triangle.

a = 48/2 = 24 m

b = h = ?

c = 51 meters

Solution

a^2 + b^2 = 51^2 Substitute for b^2 = h^2

24^2 + h^2 = 51^2 Expand 24^2 and 51^2

576 + h^2 = 2601 Subtract 576 from both sides

h^2 = 2601 - 576

h^2 = 2025 Take the square root of both sides

h = 45

Area

Area = 1/2 b * h

Area = 1/2 48 * 45

Area = 1080

Remark

Notice that to find h you only use 1/2 of 48 because that is the base of the right triangle.

To find the area, you need to use all of 48 because 48 is the full length of the base.

5 0

3 years ago

The graph of f (x)= x² has been translated 4 units down.

weeeeeb [17]

Answer:

the new equation is f(x)=x^2-4

vertex- (0,-4)

zeros- (-2,2)

y-intercept- (-4)

and it has a minimum

Step-by-step explanation:

4 0

2 years ago