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3 years ago

The lengths of the diagonals of a rhombus are 2x and 10x. What expression gives the perimeter of the rhombus?

Mathematics

1 answer:

True [87]3 years ago

6 0

Answer:

$P=4x\sqrt{26}\ units$

Step-by-step explanation:

we know that

The sides of a rhombus are all congruent and the diagonals are perpendicular bisectors of each other

Applying the Pythagorean Theorem

$c^2=a^2+b^2$

where

c is the length side of the rhombus

a and b are the semi-diagonals

we have

$a=2x/2=x\ units\\b=10x/2=5x\ units$

substitute the values

$c^2=x^2+(5x)^2$

$c^2=26x^2$

$c=x\sqrt{26}\ units$

To find out the perimeter of the rhombus multiply the length side by 4

$P=(4)(x\sqrt{26})$

$P=4x\sqrt{26}\ units$

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A quality-conscious disk manufacturer wishes to know the fraction of disks his company makes which are defective. Step 2 of 2 :

const2013 [10]

Answer:

The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

Suppose a sample of 1067 floppy disks is drawn. Of these disks, 74 were defective.

This means that $n = 1067, \pi = \frac{74}{1067} = 0.069$

80% confidence level

So $\alpha = 0.2$ , z is the value of Z that has a pvalue of $1 - \frac{0.2}{2} = 0.9$ , so $Z = 1.28$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.069 - 1.28\sqrt{\frac{0.069*0.931}{1067}} = 0.059$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.069 + 1.28\sqrt{\frac{0.069*0.931}{1067}} = 0.079$

The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).

7 0

2 years ago

What is the square root of 265

Maru [420]

The answer is 16.27 rounded to the nearest hundredth

4 0

2 years ago

Read 2 more answers

The set of ordered pairs below represents a function.

ArbitrLikvidat [17]

Given:

The set of ordered pairs below represents a function.

{(–9, 1), (–5, 2), (0, 7), (1, 3), (6, –10)}

Josiah claims that the ordered pair (6, –10) can be replaced with any ordered pair and the set will still represent a function.

To find:

All the ordered pairs that could be used to show that this claim is incorrect.

Solution:

We need to find the ordered pairs that can be replaced with (6,-10) and for which the set is not a function.

A relation is called function if there exist a unique output for each input.

If (-9,-6) is replaces with (6,-10), then the set has two outputs y=1 and y=-6 for x=-9. So, the claim is incorrect.

If (1,12) is replaces with (6,-10), then the set has two outputs y=12 and y=3 for x=1. So, the claim is incorrect.

If (-10,-10) is replaces with (6,-10), then there exist unique output for each input. So, the claim is correct.

If (4,7) is replaces with (6,-10), then there exist unique output for each input. So, the claim is correct.

If (-5,1) is replaces with (6,-10), then the set has two outputs y=1 and y=2 for x=-5. So, the claim is incorrect.

Therefore, the correct options are (a), (b) and (e).

8 0

2 years ago

Do this for a brain thingy!!!!<br> 1087^{2}-12(3)=

Gre4nikov [31]

Answer:

1181533

Step-by-step explanation:

It's called brainliest.

You can use Math way for that btw.

3 0

2 years ago

The acceleration of a Maserati (sports car) is proportional to the difference between 250 km/h and its velocity. If the car can

Igoryamba

Answer:

a) The differential equation for the velocity is given by

(dv/dt) = k(250 - v)

b) v(t) = 250 - e⁽⁵•⁵² ⁻ ᵏᵗ⁾

With units of km/h

Step-by-step explanation:

Acceleration, a ∝ (250 - v)

But acceleration is widely given as dv/dt

(dv/dt) ∝ (250 - v)

(dv/dt) = k(250 - v)

where k = constant of proportionality

(dv/dt) = k(250 - v)

b) (dv/dt) = k(250 - v)

dv/(250 - v) = k dt

∫ dv/(250 - v) = ∫ k dt

- In (250 - v) = kt + c (where c is the constant of integration)

v(0) = 0; meaning, at t = 0, v = 0

- In 250 = 0 + C

c = - In 250 = - 5.52

- In (250 - v) = kt - 5.52

In (250 - v) = 5.52 - kt

250 - v = e⁽⁵•⁵² ⁻ ᵏᵗ⁾

v = 250 - e⁽⁵•⁵² ⁻ ᵏᵗ⁾

With units of km/h

i hope this work for you

and sory if im wrang

4 0

2 years ago