Given that,
KM bisects ∠LKJ.
m∠LKM = 4x + 12 and m∠MKJ = 6x - 6
To find,
The value of x.
Solution,
As KM bisects ∠LKJ. It would mean that,
m∠LKM = m∠MKJ
Putting the above values,
4x+12=6x-6
We can solve the above equations as follows :
4x-6x=-12-6
-2x=-18
x=9
Therefore, the value of x is equal to 9.
Answer:
a^3 + a^2
Step-by-step explanation:
Distribute the term left of each set of parentheses, then combine like terms.
-a²(3a - 5) + 4a(a² - a) =
= -3a^3 + 5a^2 + 4a^3 - 4a^2
= a^3 + a^2
Step-by-step explanation:
3x + 1 = 5x
Bringing like terms on one side
1 = 5x - 3x
1 = 2x
1/2 = x
The longest side of a right triangle is hypotenuse
