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geniusboy [140]
3 years ago
13

Solve for x 6x + 7y = –2

Mathematics
1 answer:
coldgirl [10]3 years ago
6 0

Answer:

x = -7 over 6y plus -1 over 3

Step-by-step explanation:

Add -7y to both sides.

Divide both sides by 6.

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PLEASEEE HELP ME ANSWER THIS QUESTION!!!!!
sasho [114]

the screen is black what's the question?

4 0
3 years ago
If p→qp→q, and q→rq→r, then thats all it says
Angelina_Jolie [31]
Answer: then q→r

Explanation:

If p → q

and q →r , then  you can use the law of transitivity to conclude

q→r.

That is a basic law of sillogisms.

An example will help you to understand the transivity law:

Make p, stand for 3 > 3/4, q stand for 3/4 > 15 / 20, the you can conclude that 3 > 15 / 20.

3 > 3/4

3 /4 > 15 / 20

Then, 3 > 15 /20.

This is, from the fact that you know that 3 is gretar than 3/4 and that 3/4 is greater than 15/20, you can conclude that 3 > 15 / 20. That is transitivity and is a law of logic, which you can use to get conclusions.
8 0
3 years ago
Donovan took a math test and got 20 correct questions and 5 incorrect answers. What was the percentage of correct answers?
solong [7]

ANSWER

80%

EXPLANATION

Donovan got 20 questions correct and 5 questions incorrect.

This means that the total number of questions he attempted in the test is the sum of correct and incorrect questions:

Total = 20 + 5

Total = 25

To find the percentage of correct answers, we have to divide the number of correct answers by the total number of questions attempted and multiply by 100 (per cent).

That is:

\begin{gathered} \frac{20}{25}\cdot\text{ 100 = }\frac{4}{5}\cdot\text{ 100} \\ =\text{ 80\%} \end{gathered}

That is the percentage of correct answers.

3 0
1 year ago
You have just bought 4 bottles of water containing 750 ml each. How many litres of water do you have in total?
gulaghasi [49]
You have 187.5 because you divide 750 by 4



8 0
3 years ago
Read 2 more answers
Coefficiants of (2x+y)^4​
sattari [20]

By the binomial theorem,

(2x+y)^4=\displaystyle\sum_{k=0}^4\binom 4k(2x)^{4-k}y^k=\sum_{k=0}^4\binom 4k2^{4-k}x^{4-k}y^k

where

\dbinom nk=\dfrac{n!}{k!(n-k)!}

Then the coefficients of the x^{4-k}y^k terms in the expansion are, in order from k=0 to k=4,

\dbinom 402^{4-0}=1\cdot2^4=16

\dbinom412^{4-1}=4\cdot2^3=32

\dbinom422^{4-2}=6\cdot2^2=24

\dbinom432^{4-3}=4\cdot2^1=8

\dbinom442^{4-4}=1\cdot2^0=1

3 0
3 years ago
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