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user100 [1]
4 years ago
11

Find the approximate solution of this system of equations.

Mathematics
1 answer:
Anit [1.1K]4 years ago
3 0
Y = x^2 + 5x + 3
y = √(2x + 5)

Using a calculator, put equation 1 in y(sub1) and equation 2 in y(sub2).
Graph the equations and fin the point of intersection.
If using a TI 83/84 calculator, to find the point of intersection: 2nd CALC #5.

LETTER B
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Natasha2012 [34]

Answer: D The square root of 100 is 10. Or,

√100 = 10

Step-by-step explanation:

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A cheetah ran 300 feet in 2.92 secods. What was the cheetahs average speed in miles per hou? Show your work.
Tom [10]
Start by converting 300 feet to miles and 2.92 seconds to hours.

300 feet      1 mile
----------- x -------------- = ?
     1           5280 feet

2.92 sec              1 hr
----------------- * ---------------- =  ?
        1               3600 sec

Reduce each of the above fractions.  Then convert  300 feet
                                                                                  -------------- to the 
                                                                                    2.92 sec

equivalent speed / rate in mph using the converstion factors you derived earlier.
6 0
3 years ago
How do you write equations for horizontal and vertical lines?
NemiM [27]

Answer:

y=_

x=_

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8 0
3 years ago
A piece of cardboard is 15 inches by 30 inches. A square is to be cut from each corner and the sides folded up to make an open-t
solmaris [256]

Answer:

Maximum volume = 649.519 cubic inches

Step-by-step explanation:

A rectangular piece of cardboard of side 15 inches by 30 inches is cut in such that a square is cut from each corner. Let x be the side of this square cut. When it was folded to make the box the height of box becomes x, length becomes (30-2x) and the width becomes (15-2x).

Volume is given by  

V = V = Length\times Width\times Height\\V = (30 - 2x)(15-2x)x= 4x^3-90x^2+450x\\So,\\V(x) = 4x^3-90x^2+450x

First, we differentiate V(x) with respect to x, to get,

\frac{d(V(x))}{dx} = \frac{d(4x^3-12x^2+9x)}{dx} = 12x^2 - 180x +450

Equating the first derivative to zero, we get,

\frac{d(V(x))}{dx} = 0\\\\12x^2 - 180x +450 = 0

Solving, with the help of quadratic formula, we get,

x = \displaystyle\frac{5(3+\sqrt{3})}{2}, \frac{5(3-\sqrt{3})}{2},

Again differentiation V(x), with respect to x, we get,

\frac{d^2(V(x))}{dx^2} = 24x - 180

At x =

\displaystyle\frac{5(3-\sqrt{3})}{2},

\frac{d^2(V(x))}{dx^2} < 0

Thus, by double derivative test, the maxima occurs at

x = \displaystyle\frac{5(3-\sqrt{3})}{2} for V(x).

Thus, largest volume the box can have occurs when x = \displaystyle\frac{5(3-\sqrt{3})}{2}}.

Maximum volume =

V(\displaystyle\frac{5(3-\sqrt{3})}{2}) = (30 - 2x)(15-2x)x = 649.5191\text{ cubic inches}

8 0
3 years ago
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