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aivan3 [116]
3 years ago
15

Just the answer please

Mathematics
1 answer:
nordsb [41]3 years ago
3 0

Answer:b is the right choice hopefully dont be mad if it is wrong

Step-by-step explanation:

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X and y intercepts of y = 360 - 8x
skad [1K]

Answer:

Step-by-step explanation:

8 0
4 years ago
Which statement is sometimes, but not always, true?
lidiya [134]
The statement that is sometimes, but not always true is:
B ) A parallelogram is a rectangle.
Other statements are always true.
8 0
4 years ago
Read 2 more answers
Un barco que hace cruceros por el mar Caribe dispone de camarotes de una plaza y de dos plazas. Si en total hay 215 camarotes y
prisoha [69]

Answer:

- There are 71 one-quarter cabins and 144 two-seater cabins on the cruise ship.

- Hay 71 cabinas de un asiento y 144 cabinas de dos asientos en el crucero.

Step-by-step explanation:

English Translation

A ship that cruises in the Caribbean Sea has one and two-seater cabins. If there are 215 cabins and 359 seats in total, find out how many cabins there are of each type.

Let the number of one seater cabins be x

Let the number of two seater cabins be y

There are x seats on the one seater cabins and there are 2y seats in total for the two seater cabins

x + y = 215 (eqn 1)

x + 2y = 359 (eqn 2)

Subtract eqn 1 from eqn 2

y = 359 - 215 = 144

x + y = 215

x = 215 - y = 215 - 144 = 71

There are 71 one-quarter cabins and 144 two-seater cabins on the cruise ship.

In Spanish/En español

Deje que el número de cabinas de un asiento sea x

Deje que el número de cabinas de dos plazas sea y

Hay x asientos en las cabinas de un asiento y hay 2 asientos en total para las cabinas de dos asientos

x + y = 215 (ecuación 1)

x + 2y = 359 (ecuación 2)

Resta la ecuación 1 de la ecuación

2 y = 359 - 215 = 144

x + y = 215

x = 215 - y = 215 - 144 = 71

Hay 71 cabinas de un asiento y 144 cabinas de dos asientos en el crucero.

Hope this Helps!!!

4 0
3 years ago
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The surface area of this square pyramid is 112 cm^2!
Hope this helps <3
5 0
3 years ago
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Simplify [2 (cos 210 + i sin 210)]^2
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2{(cos^210+isin^210)}^2

2(cos^210-sin^10+2i*cos10*sin10)

2(cos20+i*sin20)

cos^2Ф-sin^2Ф=cos2Ф and 2sinФcosФ=sin2Ф here Ф=10°

4 0
3 years ago
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