Given: It is given that the length of the painting is 24 inches and the width is 11 inches.
To find: Area of the mat
Solution:
The watercolor painting is 24 inches long by 11 inches wide.
So, the area of the painting is:
![\text{Area of painting}=l\times b](https://tex.z-dn.net/?f=%5Ctext%7BArea%20of%20painting%7D%3Dl%5Ctimes%20b)
![\text{Area of painting}=24\times 11](https://tex.z-dn.net/?f=%5Ctext%7BArea%20of%20painting%7D%3D24%5Ctimes%2011)
![\text{Area of painting}=264 \text{ in}^2](https://tex.z-dn.net/?f=%5Ctext%7BArea%20of%20painting%7D%3D264%20%5Ctext%7B%20in%7D%5E2)
The length of painting with mat is = 24 in + 3 in + 3 in = 30 in
The width of painting with mat = 11 in + 3 in + 3 in = 17 in
![\text{Area of painting with mat}=30\times 17](https://tex.z-dn.net/?f=%5Ctext%7BArea%20of%20painting%20with%20mat%7D%3D30%5Ctimes%2017)
![\text{Area of painting with mat}=510 \text{ in}^2](https://tex.z-dn.net/?f=%5Ctext%7BArea%20of%20painting%20with%20mat%7D%3D510%20%5Ctext%7B%20in%7D%5E2)
Now to calculate the area of mat subtracts the area of painting from the area of the mat.
![\text{Area of mat}=\text{Area of painting with mat}-\text{Area of painting}\\](https://tex.z-dn.net/?f=%5Ctext%7BArea%20of%20mat%7D%3D%5Ctext%7BArea%20of%20painting%20with%20mat%7D-%5Ctext%7BArea%20of%20painting%7D%5C%5C)
![\text{Area of mat}=510-264](https://tex.z-dn.net/?f=%5Ctext%7BArea%20of%20mat%7D%3D510-264)
![\text{Area of mat}=246 \text{ in}^2](https://tex.z-dn.net/?f=%5Ctext%7BArea%20of%20mat%7D%3D246%20%5Ctext%7B%20in%7D%5E2)
Hence, the area of the mat is 246 in².
2.6 gr = 2,600 mgr
2,600 mgr /325=8
Answer is 8 capsules
Answer:
83
Step-by-step explanation:
f(x) = 7x - 1
Put x as 12.
f(12) = 7(12) - 1
f(12) = 84 - 1
f(12) = 83
4 hours. You divide 240 by 60 because you travel 240 total miles and you 60 mph and you will get 4 and it will be 4 hours