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Sholpan [36]
3 years ago
14

If sin(x) = 0.28, what is cos(90° - x)?

Mathematics
2 answers:
nevsk [136]3 years ago
5 0
Cos (90-x) x is 28. I hope this helps you.
Ilya [14]3 years ago
5 0

Answer:

The answer is 0.28.

Step-by-step explanation:

We know that,

A trigonometric property is,

sin A = cos (90^{\circ} -A)

Where A is any angle,

Given,

sin x = 0.28

By the above property,

sin x = cos (90^{\circ}-x)

\implies cos (90^{\circ}-x) = 0.28

Hence, the answer would be 0.28.

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I NEED HELP WILL GIVE BRAINLIEST!! PLEASE HELP ME ASAP!!!!
GenaCL600 [577]

Answer:

A. The length of the second leg is 8.5 inches

B. The length of the three-dimensional diagonal is 9.9 inches

Step-by-step explanation:

Let us revise the relation between the hypotenuse and the two legs of a right triangle

(hypotenuse)² = (vertical leg)² + (horizontal leg)²

∵ The length of the rectangular box = 8 inches

∵ The width of the rectangular box = 3 inches

∵ The height of the rectangular box = 5 inches

∵ Length and width are perpendicular to each other

∴ The Δ whose legs are 3 and 8 is a right triangle

In the right Δ whose legs are 3 and 8

∵ (hypotenuse)² = (3)² + (8)²

∴ (hypotenuse)² = 9 + 64

∴ (hypotenuse)² = 73

- Take √  for both sides

∴ hypotenuse = \sqrt{73} = 8.544003745

- Round it to the nearest tenth of one inch

∴ hypotenuse = 8.5 inches

A.

The 3-dimensional diagonal is the hypotenuse of a right triangle whose legs are the vertical edge and the hypotenuse of the right triangle whose legs are 3 and 8

∵ The hypotenuse of the right triangle whose legs are 3 and

   8 is 8.5 inches

∴ The length of the second leg is 8.5 inches

B.

In the right triangle whose hypotenuse is the 3-dimensional diagonal and legs are the vertical edge , the hypotenuse of the right triangle whose legs are 3 and 8

∵ (3-dimensional diagonal)² = (5)² + (73)²

∴ (3-dimensional diagonal)² = 25 + 73

∴ (3-dimensional diagonal)² = 98

- Take √ for both sides

∴ 3-dimensional diagonal = \sqrt{98} = 9.899494937

- Round it to the nearest tenth of an inch

∴ 3-dimensional diagonal = 9.9 inches

∴ The length of the three-dimensional diagonal is 9.9 inches

<em>V.I.N: you can find the length of the  three-dimensional diagonal by using this rule → </em>d=\sqrt{l^{2}+w^{2}+h^{2}}<em> </em>

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Answer:

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Step-by-step explanation:

12 cups of sugar for 6 dozen cookies.

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3 years ago
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The steps are to first distribute the 1/3 into (x-9) and then to move the +6 on the left over to the right:

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y + 6 = 1/3(x-9) becomes y + 6 = 1/3x-3

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