How do you estimate the sum or difference of 5/12 + 7/8
1 answer:
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Answer:
The probability is 0.02667
Step-by-step explanation:
Let's call D1 the event that the first radio is defective and D2 the event that the second radio is defective.
So, if we select both radios any factory, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:
P(D2/D1) = P(D2∩D1)/P(D1)
Taking into account that 0.02 is the probability that a radio produced at factory A is defective, P(D2/D1) for factory A is:
At the same way, if both radios are from factory B, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:
Finally, if both radios are from factory C, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:
So, if the radios are equally likely to have been any factory, the probability to select both radios from any of the factories A, B or C are respectively:
P(A)=1/3
P(B)=1/3
P(C)=1/3
Then, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:
P(D2/D1) = (1/3)*(0.02) + (1/3)*(0.01) + (1/3)*(0.05)
P(D2/D1) = 0.02667
Answer:
the answer is 3
Step-by-step explanation:
First change the whole number (3) to quaters or fraction
3x =
Now, add
+
=
Since, we have the same common denominator
now divide
14÷4 =3.5 = 3
Therefore, there are 3 of 3/4 with a remainder of in 3
.