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Nezavi [6.7K]
3 years ago
5

How do you estimate the sum or difference of 5/12 + 7/8​

Mathematics
1 answer:
igomit [66]3 years ago
5 0

5/12 is about 6/12 or 1/2 and 7/8 is about 8/8 or 1 so it would be about 1 1/2 as ur answer

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3 years ago
G with the definition of covariance, prove cov[(ay − b),(cy − d)] = accov(x, y ), where x, y are random variables and a, b, c, d
____ [38]

By definition of covariance,


\mathrm{Cov}(X,Y)=\mathbb E[(X-\mathbb E[X])(Y-\mathbb E[Y])]


\mathrm{Cov}(X,Y)=\mathbb E[XY-\mathbb E[X]Y-X\mathbb E[Y]+\mathbb E[X]\mathbb E[Y]]=\mathbb E[XY]-\mathbb E[X]\mathbb E[Y]


We have


\mathbb E[(aX-b)(cY-d)]=\mathbb E[acXY-adX-bcY+bd]

=ac\mathbb E[XY]-ad\mathbb E[X]-bc\mathbb E[Y]+bd


\mathbb E[aX-b]=a\mathbb E[X]-b


\mathbb E[cY-d]=c\mathbb E[Y]-d


\mathbb E[aX-b]\mathbb E[cY-d]=ac\mathbb E[X]\mathbb E[Y]-ad\mathbb E[X]-bc\mathbb E[Y]+bd


Putting everything together, we find the covariance reduces to


\mathrm{Cov}(aX-b,cY-d)=ac(\mathbb E[XY]-\mathbb E[X]\mathbb E[Y])=ac\mathrm{Cov}(X,Y)


as desired.

5 0
3 years ago
Find the sum of the first 8 terms of the sequence. <br><br> 1, -3, -7, -11, ...
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1+(-3)+(-7)+(-11)+(-15)+(-19)+(-23)+(-27) = \\1-3-7-11-15-19-23-27 = \\-35-19-23-27= \\-35-19-50=\boxed{-104}

Hope this helps.

r3t40

4 0
3 years ago
Simplify the expression 2/3÷(-4)-[1/6-8/6]​
mash [69]

Answer:

1

Step-by-step explanation:

<em>⇒2/3 ÷ (-4) - [ 1/6 - 8/6]</em>

<em>⇒2/3 / (-4) - [- 7/6]</em>

<em>⇒-1/6 + 7/6</em>

<em>⇒6/6</em>

<em>⇒1</em>

<em />

4 0
3 years ago
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