Answer:
Step-by-step explanation:
Given
--- interval
Required
The probability density of the volume of the cube
The volume of a cube is:
For a uniform distribution, we have:
and
implies that:
So, we have:
Solve
Recall that:
Make x the subject
So, the cumulative density is:
becomes
The CDF is:
Integrate
![F(x) = [v]\limits^{v^\frac{1}{3}}_9](https://tex.z-dn.net/?f=F%28x%29%20%3D%20%5Bv%5D%5Climits%5E%7Bv%5E%5Cfrac%7B1%7D%7B3%7D%7D_9)
Expand
The density function of the volume F(v) is:
Differentiate F(x) to give:
So:
Hey there!!
The area given : 25 square yards
We will find the length of the square.
Square area = side²
side² = 25
side = √25
side = 5 yards.
Now convert this into inches
1 yard --> 36 inches
5 yards --> 180 inches
Area = 180²
Area = 32400 inches²
Hope my answer helps!!
2 is correct, because:
1) we have a close interval
2)we must have node on x=-5
