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Sauron [17]
3 years ago
13

Y = 0.115x + 0.0045 , y = 0.499x – 0.22 solve for x

Mathematics
1 answer:
enyata [817]3 years ago
6 0

Answer:

x=0.5612

Step-by-step explanation:

-Given the functions:

y=0.115x+0.0045\ \ \ \ ...i\\\\y=0.499x-0.22\ \ \ \ \ ...ii

We subtract equation i from ii to eliminate y and solve for x:

ii-i\\\\0=0.384x-0.2155\\\\0.384x=0.2155\\\\x=0.5612

Hence, the value of x is 0.5612

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Please help thank you !
Musya8 [376]

Answer:

6.6 cm and 14.6 cm

Step-by-step explanation:

(a)

the length of arc AB is calculated as

AB = circumference of circle × fraction of circle

     = 2πr × \frac{95}{360}

     = 2π × 4 × \frac{95}{360}

     = 8π × \frac{95}{360}

     = \frac{8\pi (95)}{360}

     ≈ 6.6 cm ( to the nearest tenth )

(b)

the perimeter (P) of sector AOB is

P = r + r + AB = 4 + 4 + 6.6 = 14.6 cm

5 0
2 years ago
Read 2 more answers
What is the answer to the equation 4a+26-9a-17=26?
podryga [215]
First you have to put all of your common numbers together. 4a and 9a go together. You then subtract those because 9 is negative (-9). Then you get -5a. Now move on to your other numbers. You have 26 and 17. 17 is negative as well (-17), so you subtract it from 26. That gives you 9.
Your new equation is -5a + 9 = 26
Now you subtract 9 from both sides. Your positive (+9) will cancel out with your negative (-9). Then subtract it from 26. 9 minus 26 is 17. 
Now your equation is -5a = 17
Since it's negative, you're going to add it (5) to both sides. 
Your 5's cancel out, and 17 + 5 is 22. 
a = 22
22 is the answer 

5 0
3 years ago
Which of the following points is a solution of y ≤ -|x| - 1?<br><br> (-1, -3)<br> (0, 0)<br> (1, -1)
alexdok [17]
Y + 1 \leq -|x|
-y - 1 \geq |x|
-(-y - 1) \leq x \leq -y - 1
(0, 0)

Answer: B).
3 0
3 years ago
Read 2 more answers
Given the equation 5x − 4 = –2(3x + 2), solve for the variable. Explain each step and justify your process.
blagie [28]
A.
5x-4=-2(3x+2) \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\&#10;5x-4=-2 \times 3x-2 \times 2 \\&#10;5x-4=-6x-4 \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 6x to both sides} \\&#10;11x-4=-4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 4 to both sides} \\&#10;11x=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{divide both sides by 11} \\&#10;x=0

B.
3(2x-4)=5x-1 \\&#10;6x-12=5x-1 \\&#10;\boxed{11x-12=-1} \Leftarrow \hbox{the first mistake} \\&#10;11x=11 \\&#10;\boxed{x=11} \Leftarrow \hbox{the second mistake}

Megan's solution isn't correct.
The first mistake: she subtracted 5x from the right-hand side of the equation, but added 5x to the left-hand side.
The second mistake: she divided the right-hand side of the equation by 11, but didn't divide the left-hand side.

The correct solution:
3(2x-4)=5x-1 \ \ \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\&#10;3 \times 2x+3 \times (-4)=5x-1 \\ 6x-12=5x-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{subtract 5x from both sides} \\&#10;x-12=-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  |\hbox{add 12 to both sides} \\&#10;x=11
3 0
3 years ago
Quadrilateral OPQR is inscribed inside a circle as shown below. What is the measure of angle Q? You must show all work and calcu
viktelen [127]
Hello,

Angles y and 3y+8 are supplementaries since the quadrilater is inscribed

y+3y+8=180
==>4y=172
==>y=43 (°)
8 0
3 years ago
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