Answer:
1 Expandir.
-28=-21x-28+21x
−28=−21x−28+21x
2 Simplifica -21x-28+21x−21x−28+21x a -28−28.
-28=-28
−28=−28
3 Ya que ambos lados son iguales, hay infinitas soluciones.
Soluciones Infinitas
Step-by-step explanation:
Answer: A & C
Step-by-step explanation:
So lets try to prove it,
So let's consider the function f(x) = x^2.
Since f(x) is a polynomial, then it is continuous on the interval (- infinity, + infinity).
Using the Intermediate Value Theorem,
it would be enough to show that at some point a f(x) is less than 2 and at some point b f(x) is greater than 2. For example, let a = 0 and b = 3.
Therefore, f(0) = 0, which is less than 2, and f(3) = 9, which is greater than 2. Applying IVT to f(x) = x^2 on the interval [0,3}.
Learn more about Intermediate Value Theorem on:
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