What would happenen if we were to have a solar eclipse and a lunar eclipse

Calculate the amount of heat energy, in units of kilojoules, required to convert 50.0 g of liquid ethanol, CH3CH2OH, at 25.5°C t

tamaranim1 [39]

Answer:

42.1 kj

Explanation:

Given data:

Molar heat of vaporization = 3.86×10⁴ j/mol

Mass of ethanol = 50 g

Amount of heat required to convert into gaseous form = ?

Solution:

First of all we will calculate the number of moles of ethanol.

Number of moles = mass/ molar mass

Number of moles = 50.0 g/ 46.07 g/mol

Number of moles = 1.09 mol

H(vap) = number of moles × molar heat of vaporization

H(vap) = 1.09 mol × 3.86×10⁴ j/mol

H(vap) = 4.21×10⁴ j

In Kj:

4.21×10⁴ / 1000 = 42.1 kj

7 0

3 years ago

Lithium and nitrogen react in a combination reaction to produce lithium nitride: 6Li (s) + N2 (g) → 2Li3N (s) In a particular ex

seraphim [82]

Answer: 6.71 g

Explanation: $6Li(s)+N_2(g)\rightarrow 2Li_3N$

${\text{no of moles}}=\frac{\text{Given mass}}{\text{Molar mass}}$

${\text {moles of lithium}}=\frac{4g}{6.914g/mol}=0.578moles$

$\text{moles of nitrogen}=\frac{4g}{28g/mol}=0.143moles$

Limiting reagent is the reagent which limits the formation of product. Excess reagent is one which is in excess and thus remains unreacted.

Thus lithium is the limiting reagent and nitrogen is the excess reagent.

As can be seen from the balanced chemical equation, 6 moles of lithium reacts with 1 mole of nitrogen to give 2 moles of lithium nitride.

Thus 0.578 moles of lithium react with 0.096 moles of nitrogen.

6 moles of lithium give = 2 moles of lithium nitride

Thus 0.578 moles of lithium give= $\frac{2}{6}\times {0.578}=0.19moles$ of lithium nitride.

Mass of lithium nitride $Li_3N={\text {no of moles}}\times {\text {Molecular mass}}$

Mass of lithium nitride $Li_3N$ = ${0.192moles}\times {34.83g/mol}=6.71g$

8 0

3 years ago

In a desert ecosystem, coyotes and rattlesnakes both eat the same type of mouse as a primary part of their diets. Recently, coyo

Alex Ar [27]

Answer:

there primary food source will still be the same

Explanation:

they will still ear mice but coyotesmay eat Humans if they are close because once they see humans they think they will be killed its there protectiong

5 0

4 years ago

If 125 cal of heat is applied to a 60.0g piece of copper at 21.0 degrees C, what will be the final temperature? the specific hea

MaRussiya [10]

Q=mcT

125cal=(60.0g)(0.0920)(T-21)

[(125)/(60)(0.0920)]+21=T2

T2=43.6C

5 0

3 years ago

Write the beta decay equation for the following isotope: 15/6 C?

vesna_86 [32]

Answer:

$\rm _{6}^{15}\text{C} \longrightarrow \, _{-1}^{0}\text{e} + \, _{7}^{15}\text{N}$

Explanation:

The unbalanced nuclear equation is

$\rm _{6}^{15}\text{C} \longrightarrow \, _{-1}^{0}\text{e} + \, ?$

Let's write the question mark as a nuclear symbol.

$\rm _{6}^{15}\text{C} \longrightarrow \, _{-1}^{0}\text{e} + \, _{Z}^{A}\text{X}$

The main point to remember in balancing nuclear equations is that the sums of the superscripts and the subscripts must be the same on each side of the equation.

Then

15 = 0 + A, so A = 15 - 0 = 15, and

6 = -1 + Z, so Z = 6 + 1 = 7

Then, your nuclear equation becomes

$\rm _{6}^{15}\text{C} \longrightarrow \, _{-1}^{0}\text{e} + \, _{7}^{15}\text{X}$

Element 7 is nitrogen, so the balanced nuclear equation is

$\rm _{6}^{15}\text{C} \longrightarrow \, _{-1}^{0}\text{e} + \, _{7}^{15}\text{N}$

8 0

4 years ago