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VashaNatasha [74]
3 years ago
14

Lithium and nitrogen react in a combination reaction to produce lithium nitride: 6Li (s) + N2 (g) → 2Li3N (s) In a particular ex

periment, 4.00-g samples of each reagent are reacted. The theoretical yield of lithium nitride is ________ g.
Chemistry
1 answer:
seraphim [82]3 years ago
8 0

Answer: 6.71 g

Explanation: 6Li(s)+N_2(g)\rightarrow 2Li_3N

{\text{no of moles}}=\frac{\text{Given mass}}{\text{Molar mass}}

{\text {moles of lithium}}=\frac{4g}{6.914g/mol}=0.578moles

\text{moles of nitrogen}=\frac{4g}{28g/mol}=0.143moles

Limiting reagent is the reagent which limits the formation of product. Excess reagent is one which is in excess and thus remains unreacted.

Thus lithium is the limiting reagent and nitrogen is the excess reagent.

As can be seen from the balanced chemical equation,  6 moles of lithium reacts with 1 mole of nitrogen to give 2 moles of lithium nitride.

Thus 0.578 moles of lithium react with 0.096 moles of nitrogen.

6 moles of lithium give = 2 moles of lithium nitride

Thus 0.578 moles of lithium give=\frac{2}{6}\times {0.578}=0.19moles of lithium nitride.

Mass of lithium nitride Li_3N={\text {no of moles}}\times {\text {Molecular mass}}

Mass of lithium nitrideLi_3N={0.192moles}\times {34.83g/mol}=6.71g


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