The answer is:
11.18
Hope This Helps!!
:)
I would like to have a patient and good teacher,who is not angry or stressed,or give us lots of homeworks.
Hope I helped u :)
The least number of quadratic system can have is Two real solutions or no real solutions.
Step-by-step explanation:
First we have to same the bases.
As we know 8=2^3.
Replace 8 with 2^3.
Like this .
2^3x=2^3(2x+1).
Now 3x=3(2x+1) distribute 3 by the Barker.
3x=6x+3.
6x+3=3x.
6x-3x=-3.
3x=-3.
X=-1.
