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Ira Lisetskai [31]
3 years ago
10

If a triangle has 23mm,20mm,13mm angles 62°,72°,46° what type of triangle is it

Mathematics
1 answer:
frutty [35]3 years ago
3 0
I would draw the triangle then it would be easier to answer. It is not an equilateral because it is not equal on all sides. Perhaps scalene because all the sides are not the same.
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0.5% of 490 is what number  show work please
Genrish500 [490]
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What is the scientific notation of 0.00734​
stich3 [128]

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4 0
3 years ago
2. US$ 1.7135
Brrunno [24]

Answer:

1577.8 US dollars are received for 1127 UK pounds.

5669.5 UK pounds are received for US$7937.3.

Step-by-step explanation:

The questions are solved by proportions, using a rule of three.

How many US dollars are received for 1127 UK pounds?

1 UK pound = 1.4 US dollars

1127 UK pounds - x US dollars

Applying cross multiplication:

x = 1127*1.4 = 1577.8

1577.8 US dollars are received for 1127 UK pounds.

How many UK pounds are received for US$7937.3?

1 UK pound = 1.4 US dollars

x UK pounds - 7937.3 US dollars

1.4x = 7937.3

x = \frac{7937.3}{1.4}

x = 5669.5


5669.5 UK pounds are received for US$7937.3.

4 0
3 years ago
Given H(t)=10-2t^2 , find h^-1 (t)
kobusy [5.1K]
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Not really sure to this question but I think 2+
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Explain how you could use the information that all circles are similar to show that the value of pi is a constant.
zhenek [66]

Answer:

The proof that πk(C1)=πk(C2) of course would just apply the similarity of polygons and the behavior of length and area for changes of scale. This argument does not assume a limit-based theory of length and area, because the theory of length and area for polygons in Euclidean geometry only requires dissections and rigid motions ("cut-and-paste equivalence" or equidecomposability). Any polygonal arc or region can be standardized to an interval or square by a finite number of (area and length preserving) cut-and-paste dissections. Numerical calculations involving the πk, such as ratios of particular lengths or areas, can be understood either as applying to equidecomposability classes of polygons, or the standardizations. In both interpretations, due to the similitude, the results will be the same for C1 and C2.

7 0
3 years ago
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