All categories

3 years ago

I need help understanding this ASAP PLZ!!!!

Mathematics

1 answer:

MAXImum [283]3 years ago

5 0

Answer:

$x\geq -2$

Step-by-step explanation:

well the values for x are from -2 to ∞

so we can write it as

$x\geq -2$

You might be interested in

i cant find my answer. You should really give your people the answer they are looking fo instead of giving sujestions.

Vesnalui [34]

Answer:

Did you ask a question? I just checked your profile to see if you posted any but i dont see anything except this

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

What is 3/8 divided by 4/5?

vovikov84 [41]

3/8 divided by 4/5 is the same as 3 * 5 / 8 * 4 = 15/32 or 0.46875

4 0

3 years ago

NO ONE IS HELPING PLEASE. Find the value of x in each case! IF U GET THIS I WILL MARK BRAINLIEST. 25 POINTS ON THE LINE! Thank y

Murrr4er [49]

Answer:

Step-by-step explanation:

Use corresponding angles.

Angle FBC is 180 - 147 which is 33.

This means x is 180 - 33 - Angle EBA.

EBA is 180 - 4x.

x = 180 - 33 - (180 - 4x)

x = 180 - 33 - 180 + 4x

-3x = 180 - 33 - 180

-3x = -33

3x = 33

x = 11

Please mark brainliest.

6 0

2 years ago

Find the laplace transform of f(t) = cosh kt = (e kt + e −kt)/2

iren2701 [21]

Hello there, hope I can help!

I assume you mean $L\left\{\frac{ekt+e-kt}{2}\right\}$
With that, let's begin

$\frac{ekt+e-kt}{2}=\frac{ekt}{2}+\frac{e}{2}-\frac{kt}{2} \ \textgreater \ L\left\{\frac{ekt}{2}-\frac{kt}{2}+\frac{e}{2}\right\}$

$\mathrm{Use\:the\:linearity\:property\:of\:Laplace\:Transform}$
$\mathrm{For\:functions\:}f\left(t\right),\:g\left(t\right)\mathrm{\:and\:constants\:}a,\:b$
$L\left\{a\cdot f\left(t\right)+b\cdot g\left(t\right)\right\}=a\cdot L\left\{f\left(t\right)\right\}+b\cdot L\left\{g\left(t\right)\right\}$
$\frac{ek}{2}L\left\{t\right\}+L\left\{\frac{e}{2}\right\}-\frac{k}{2}L\left\{t\right\}$

$L\left\{t\right\} \ \textgreater \ \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{t\right\}=\frac{1}{s^2} \ \textgreater \ L\left\{t\right\}=\frac{1}{s^2}$

$L\left\{\frac{e}{2}\right\} \ \textgreater \ \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{a\right\}=\frac{a}{s} \ \textgreater \ L\left\{\frac{e}{2}\right\}=\frac{\frac{e}{2}}{s} \ \textgreater \ \frac{e}{2s}$

$\frac{ek}{2}\cdot \frac{1}{s^2}+\frac{e}{2s}-\frac{k}{2}\cdot \frac{1}{s^2}$

$\frac{ek}{2}\cdot \frac{1}{s^2} \ \textgreater \ \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \ \frac{ek\cdot \:1}{2s^2} \ \textgreater \ \mathrm{Apply\:rule}\:1\cdot \:a=a$
$\frac{ek}{2s^2}$

$\frac{k}{2}\cdot \frac{1}{s^2} \ \textgreater \ \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \ \frac{k\cdot \:1}{2s^2} \ \textgreater \ \mathrm{Apply\:rule}\:1\cdot \:a=a$
$\frac{k}{2s^2}$

$\frac{ek}{2s^2}+\frac{e}{2s}-\frac{k}{2s^2}$

Hope this helps!

3 0

3 years ago

Please help

maxonik [38]

Answer:

D. -12s squared + 11st - 2t squared

Step-by-step explanation:

FOIL:

-3s(4s) - 3s(-t) + 2t(4s) + 2t(-t)

- 12s² + 3st + 8st - 2t²

Simplify.

- 12s² + 11st - 2t²

7 0

3 years ago

Read 2 more answers