Answer:
(a) what is the sample space for this chance process?
If we toss a coin three times then there are total
outcomes
The sample space associated with the given chance process is:

(b) what is the assignment of probabilities to outcomes in this sample space?
Since the given sample space has eight outcomes and we know that a fair coin is tosses three times. Therefore, the probability of all the events mentioned in the given sample space is same. Hence we have:

Step-by-step explanation:
it's an equilateral triangle so all sides are equal
using Pythagorean theorem
2(√6) raised to the power of 2 = √6 raised to the power of 2 + x raised to the power of 2
2(√6) raised to the power of 2 is 12
√6 raised to the power of 2 is 6
therefore 12=6 + x
x = 12-6
x=6
Answer:
The answer is 6ab³c(3ab + 4c)
Step-by-step explanation:
You have to collect the like-term :
18a²b⁴c + 24ab³c²
= 6(3a²b⁴c + 4ab³c²)
= 6a(3ab⁴c + 4b³c²)
= 6ab³(3abc + 4c²)
= 6ab³c(3ab + 4c)