The y-intercept of any function occurs when x=0, so we merely have to solve this function when x=0.
y = (0+2)^2 - 3
y = (2)^2 -3
y= 4-3
y=1
Therefore, our y-intercept occurs at the point (0,1). Hope that helps!
The best way to think about this value is to picture the graph of the "normal" sin wave. One period starts at (0, 0), goes up to a y value of 1 at an x value of

, goes back down to a y value of 0 at x =

, goes down to a y value of -1 at x =

and ends up completing one period at a y value of 0 and an x value of

. We can see from that what the sin ratios are at each one of those x values. When x = 0, y = 0, so the sin of 0 is 0. Check your calculator to see that this is true, but understanding the graph tells you WHY it is true.
Answer:
1,6 and 6,0 i think
Step-by-step explanation: