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3 years ago

X+8=6 you have to solve for x.

Mathematics

2 answers:

Firlakuza [10]3 years ago

8 0

Answer:

x= -2

Step-by-step explanation:

8-2=6

also, 8-8=0, 6-8= -2

x=-2

Hope this helps:)- please crown me brainliest!

Orlov [11]3 years ago

7 0

Answer:

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X/3=-19<br> What is the value of x

Molodets [167]

<h3>I'll teach you how solve X/3=-19</h3>

-----------------------------------------------

X/3=-19

Multiply both sides by 3:

3x/3= 3(-19)

Simplify:

x= -57

Your Answer Is x= -57

plz mark me as brainliest :)

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3 years ago

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4 = (8, 2)<br> y =(-1,-3)

den301095 [7]

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Which of the following fractions have the same value as 16 ÷ (–3)? Check all that apply.

Snowcat [4.5K]

Answer:

StartFraction 16 over negative 3, EndFraction StartFraction negative 16 over 3, and EndFraction Negative (StartFraction 16 over 3 EndFraction)

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Step-by-step explanation:

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3 years ago

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How many ways can Carlos choose 2 pizza toppings from a menu of 4 toppings if each topping can only be chosen once?

Ahat [919]

Answer:

30 different ways

Step-by-step explanation:

for the first topping she can choose 1 of 6 items

so she has 6 choices

and then the second topping she has 5 choices as each topping can only be chosen once

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3 0

3 years ago

Amy is pulling a wagon with a force of 30 pounds up a hill at an angle of 25°. Give the force exerted on the wagon as a vector a

Fofino [41]

Answer:

Vector (ordered pair - rectangular form)

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force ( $\vec F$ ), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

$\vec F = \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right)$ (1)

Vector (ordered pair - polar form)

$\vec F = \left(\|\vec F\|, \theta\right)$

Sum of vectorial components (linear combination)

$\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j}$ (2)

Where:

$\|\vec F\|$ - Norm of the vector force, in newtons.

$\theta$ - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

$\hat{i}$ , $\hat{j}$ - Orthogonal axes, no unit.

If we know that $\|\vec F\| = 30\,lbf$ and $\theta = 25^{\circ}$ , then the force exerted on the wagon is:

Vector (ordered pair - rectangular form)

$\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf]$

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N]$

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

8 0

3 years ago