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3 years ago

7

Solve the following for y: y-2=-6(x-(-2))

1 answer:

kap26 [50]3 years ago

4 0

Y-2=6x+12
add the 2 on both sides
y=6x+14

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What are the coordinates of the midpoint of the segment whose endpoints are A(−1, 9) and B(3, 8) ?

Mrrafil [7]

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
A&({{ -1}}\quad ,&{{ 9}})\quad 
% (c,d)
B&({{ 3}}\quad ,&{{ 8}})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left(\cfrac{{{ 3}} - {{ 1}}}{2}\quad ,\quad \cfrac{{{ 8}} + {{ 9}}}{2} \right)$

3 0

4 years ago

Write the equation of the line ?<br><br>y=?<br><br>PLEASE HELP <br><br><br>

sashaice [31]

Answer:

y=-2/3x -6

Step-by-step explanation:

y=-6 so b=-6

rise/run=-2/3

Put that into an equation of y=mx+b and you get y=-2/3x -6

5 0

3 years ago

PLEASE BE QUICK!

Svetach [21]

The answer is 0.73 hope it helps

3 0

4 years ago

Please answer!!!!!!!!!!!

Zanzabum

Answer:

C. $f(a + 2) = \dfrac{5 + a}{a - 1}$

Step-by-step explanation:

Replace x with a + 2 and simplify the expression.

$f(x) = \dfrac{3 + x}{x - 3}$

Let x = a + 2

$f(a + 2) = \dfrac{3 + a + 2}{a + 2 - 3}$

$f(a + 2) = \dfrac{5 + a}{a - 1}$

4 0

4 years ago

Read 2 more answers

The digit in the tens placeof a two digit is three times that in the units place. if the digits are reversed , the new no will b

Charra [1.4K]

If a number's ten digit is $x$ and the units digit is $y$ , then you can write the number as $10x+y$ .

Obviously, inverting the digits would lead to the number $10y+x$ .

Since this new number is 36 less than the original, we have

$10y+x = 10x+y-36 \iff 9x-9y=36\iff x-y=4$

Since we also know that the digit in the tens place is three times that in the units place, we can add an equation to form a system:

$\begin{cases}x-y=4\\x=3y\end{cases}\iff 3y-y=4\iff y=2$

And thus $x=2\cdot 3=6$

6 0

3 years ago