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viktelen [127]
3 years ago
14

Find the exact solution of the system of equations of x^2+y^2-4x-6y+4=0 and x^2-4x-3y+4=0

Mathematics
1 answer:
gavmur [86]3 years ago
7 0
We can readily know the x^2-4x+4=3y then use it to replace the same function in the first equation which refers to the 3y+y^2-6y=0 
                                                              y^2-3y=0
                                                             y(y-3)=0
                                                               y1=0 -----------y2=3
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Plz right answer=brainlyest
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Answer:

B—283 cm^2

Step-by-step explanation:

SA=πr^2 + πrl

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l=13

SA=π5^2 + π5*13

SA=π25 + π65

SA=78.5398 + 204.2035

SA=282.7433

SA=283=B

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Answer:

See below

Step-by-step explanation:

<h3>Part A</h3>
  • The graph is attached
<h3>Part B</h3>
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It has only one solution when the line mx + 1 is parallel to one part of |2x - 4|.

As per graph, we see m = 2 makes it parallel to y = 2x - 4. This is the only solution.

---------------------------

Now, as I understand, you are looking for 2 solutions instead of one. It means the line mx + 1 will have 2 points of intersection with the line |2x - 4|.

One of those solutions is attached as well, where m = 1. And you may get many more options for this.

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Step-by-step explanation:

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