5x+3y=17
3y=-5x+17
y=-5/3y + 17/3
Graph if it asks.
Pemdas helps so first you do Parentheses Exponet multiply divide add and subtract
An expression for the height of the nth bounce is 0.80X^N = Height.
<h3><u>Equations</u></h3>
Since when dropped, a super ball will bounce back to 80% of its peak height, continuing on in this way for each bounce, to determine an expression for the height of the nth bounce the following calculation must be performed:
- X = Initial value
- 80% = 0.80
- N = Number of times the ball bounces
- 0.80X^N = Height
Therefore, an expression for the height of the nth bounce is 0.80X^N = Height.
Learn more about equations in brainly.com/question/2263981
Step-by-step answer:
Given:
mean, mu = 200 m
standard deviation, sigma = 30 m
sample size, N = 5
Maximum deviation for no damage, D = 100 m
Solution:
Z-score for maximum deviation
= (D-mu)/sigma
= (100-200)/30
= -10/3
From normal distribution tables, the probability of right tail with
Z= - 10/3
is 0.9995709, which represents the probability that the parachute will open at 100m or more.
Thus, by the multiplication rule, the probability that all five parachutes will ALL open at 100m or more is the product of the individual probabilities, i.e.
P(all five safe) = 0.9995709^5 = 0.9978565
So there is an approximately 1-0.9978565 = 0.214% probability that at least one of the five parachutes will open below 100m
