((6*2)+y)+(x+15)
i hope this helps if not sorry
Answer: b= - -log10(7)+3/2
Step-by-step explanation: log 10 (7) -2b-9=-6 : b= - -log10(7)+3/2 (Decimal : b = -1.07745...)
so these are the steps how I got it I did log 10 (7)-2b-9=-6 subtract log 10 (7) -9 from both sides log 10 (7)-2b-9-(log10(7)-9)=-6-(log 10 (7) -9)
Simplify -2b= -log10(7)+3
Divide both sides by -2 -2b/2= - log 10(7)/-2+ 3/-2 if you simplify it should give you b= - -log10(7)+3/2 that should be your answer but i'm not sure those I think that's how you do it let me know if you got it right bye!
22 - 1 = -3d
21= -3d
21/-3= d
-7 = d
Bring the 1 to the other side by doing the opposite sign, so subtract 1. Solve the left side.
Bring the 3 to the other side by doing the opposite sign, so divide 21 by -3.
End with D equaling -7
The square root of 2 is 1.41
Answer:
Step-by-step explanation:
At the point where Roshonda and James meet each other, they must have covered equal distances.
Let x represent the distance that Roshonda covered while riding from school to home and also the distance covered by James while travelling in a bus from school.
Let t represent the time it took Roshonda to cover x miles.
Distance = speed × time
Therefore
x = 12 × t = 12t
James left school 0.25 hours later at a speed of 35 miles per hour. Time spent by James in covering x miles would be t - 0.25.
Distance covered would be
x = 35(t - 0.25) = 35t - 8.75
Since the distance covered is the same, then,
12t = 35t - 8.75
35t - 12t = 8.75
23t = 8.75
t = 8.75/23 = 0.38 hours
0.38 + 0.25 = 0.63 hours
0.63 × 60 = 37.8 minutes
At about 3:38 pm, they would meet
