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Volgvan
3 years ago
13

Given the points A(-10, -4) and B(14, 4), find the coordinates of the point P on the directed line segment AB that partitions AB

in the ratio 5:3.
Mathematics
1 answer:
anastassius [24]3 years ago
3 0

Answer:

P(5, 1)

Step-by-step explanation:

Segment AB is to be partitioned in a ratio of 5:3. That means the ratio of the lengths of AP to PB is 5:3. We need to find the ratio of the lengths of AP to AB.

AP/PB = 5/3

By algebra:

PB/AP = 3/5

By a rule of proportions:

(PB + AP)/AP = (3 + 5)/5

PB + AP = AP + PB = AB

AB/AP = 8/5

AP/AB = 5/8

The first part of the segment is 5/8 of the length of the segment, and the second part of the segment has length of 3/8 of the length of segment AB.

Point P is located 5/8 of the distance from point A to point B. The x-coordinate of point P is 5/8 of the difference in x-coordinates added to the x-coordinate of point A. The y-coordinate of point P is 5/8 of the difference in y-coordinates added to the y-coordinate of point A.

x-coordinate:

difference in coordinates: |14 - (-10)| = |14 + 10| = 24

5/8 of 24 = 5/8 * 24 = 15

Add 15 to the x-coordinate of point A: -10 + 15 = 5

x-coordinate of point P: 5

y-coordinate:

difference in coordinates: |4 - (-4)| = |4 + 4| = 8

5/8 of 8 = 5/8 * 8 = 5

Add 5 to the y-coordinate of point A: -4 + 5 = 1

y-coordinate of point P: 1

Answer: P(5, 1)

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Answer:

-3x+y=0

Step-by-step explanation:

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3 years ago
Consider the equation x2+4x+9=0 in standard form. Which equation shows the coefficients a, b, and c correctly substituted into t
Afina-wow [57]

Answer:

<h2>x = -2+i√5 and  -2i-√5</h2>

Step-by-step explanation:

The general form of a quadratic equation is ax²+bx+c = 0

Given the quadratic equation x²+4x+9=0 in its standard form, on comparing with the general equation we can get the value of the constant a, b and c as shown;

ax² = x²

a = 1

bx = 4x

b = 4

c = 9

The quadratic formula is given as x = -b±√(b²-4ac)/2a

Substituting the constant;

x = -4±√(4²-4(1)(9))/2(1)

x = -4 ±√(16-36)/2

x = -4±√-20/2

x = -4±(√-1*√20)/2

Note that √-1 = i

x = -4±(i√4*5)/2

x = (-4±i2√5)/2

x = -4/2±i2√5/2

x = -2±i√5

The solution to the quadratic equation are  -2+i√5 and  -2i-√5

5 0
3 years ago
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