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3 years ago

The sum of two imbers is 100. The sum of 8 and the larger number is equal to 5 times the smaller number. What is the smaller

Mathematics

2 answers:

kow [346]3 years ago

5 0

The smaller number is 18.

Step-by-step explanation:

Given,

Sum of two numbers = 100

The sum of 8 and the larger number is equal to 5 times the smaller number.

To find the smaller number.

Let,

Larger number is x and smaller number is y.

According to the problem,

x+y =100 ----- eq 1

8+x = 5y ------ eq 2

Now,

Putting the value x = 100 - y from eq 1 in eq 2 we get,

8+100-y = 5y

or, 6y = 108

or, y = 18

Hence,

The smaller number is 18.

Nookie1986 [14]3 years ago

3 0

Answer:8

Step-by-step explanation:

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Read 2 more answers

Match each of the following complex numbers with its equivalent expression.

Yanka [14]

Answer:

Therefore

$i^{110}=-1$

$i^{92}=1$

$i^{245}=i$

$i^{347}=-i$

Step-by-step explanation:

Complex Number :

A complex number is a number that can be expressed in the form

$a + bi$

where a and b are real numbers, and

' i ' is called an imaginary number.

The value of i is given as

$i=\sqrt{-1}$

Squaring both the side we get

$i^{2}=(\sqrt{-1})^{2}\\\therefore i^{2}=-1$

Therefore on substituting we get

For i^110

$i^{110}=(i^{2})^{55}=(-1)^{55}=-1$

Similarly for i^92

$i^{92}=(i^{2})^{46}=(-1)^{46}=1$

Similarly for i^245

$i^{245}=(i^{2})^{122}\times i=(-1)^{122}\times i=1\times i =i$

Similarly for i^347

$i^{347}=(i^{2})^{173}\times i=(-1)^{173}\times i=-1\times i =-i$

Therefore

$i^{110}=-1$

$i^{92}=1$

$i^{245}=i$

$i^{347}=-i$

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