Answer: 3
Step-by-step explanation:
In theory we know that the equation of a linear function is expressed as
Eq.(1): y = m*x + c,
where m is the slope and c is a constant.
From the table we know the values of x and y, so we can use any of those, but in this case lets use the first and third rows of the table and substituting in Eq.(1) we obtain a 2-equation system as follow:
Point (-2,-2) gives: -2 = (-2)*m + c Eq.(2)
Point (0,4) gives: 4 = (0)*m + c Eq.(3)
Now rearranging Eq.(2) we get: -2 = -2*m + c <=> -2 - c = -2m Eq.(4)
Then rearranging Eq.(3) we get: 4 = 0 + c <=> c = 4
Plugging the value of c in Eq.(4) we get:
-2 = -2m + 4 <=> -2 - 4 = - 2m <=> -6 = -2m <=> m = 3
So finally and from Eq.(1) we obtain
y = 3x + c
Answer:
l=√261 in
Step-by-step explanation:
l²=(12/2)²+15²
l²=6²+15²
l²=36+225
l²=261
l=√261 in ≈ 16.1555 in
Answer:
B-28+19m
Explanation:
1.) The radius which is OB also is
10.0.
It is a right triangle so c^2 = a^2 + b^2 : In this case, AO^2 = AB^2 + OB^2
11.4^2 = 6^2 + OB^2
129.96 = 36 + OB^2
OB^2 = 93.96
OB = 9.69
Note: I think your given is wrong since there's no 9.69 in the choices. But a similar problem is found on the internet and the given are <span> AB = 6 and AO = 11.7. So If these are the given data, the answer would be 10.0, Letter D.
2.) The perimeter is
64.
</span> In an incircle, the distances between a vertex and the two nearest tangent points are equal to each other.
JA = JB
LA = LC
KC = KB
2 × (12 + 15 + 5) = 64
3.) The measure of ZWX is
243<span>
º.
</span>A diameter forms an arc of 180°, so ZRW would equal to 180°. To get ZWX, we'll add ZRW and WX.
180° + 63° = 243°
4.) The length of AB is
58.5.
We'll get the length of CB first, by using OB^2 = OC^2 + CB^2, substitute and transpose to get CB.
CB = sqrt(32^2 - 13^2)
CB = sqrt(1024 - 169)
CB = sqrt(855)
CB = 29.24
AB is equal to 2CB.
AB = 2(29.24) = 58.5
Step-by-step explanation: In this problem, we are asked to graph the equation y = 2x + 3 given a domain of all real numbers.
In this situation, I would first set up a chart that we can use to organize our information. On the left side of the chart, we have our different values for x that we will be plugging into the equation. On the right side of the chart, we have our different values for y that we end up with. In the middle, we have the side of the equation that contains the x which in this case is 2x + 3.
Since our domain is all real numbers, we can choose any values we want to choose to plug into the equation for x.
Let's start with the values 1, 0, and -1 just to keep things simple. Plugging a 1 into the equation for x, we have 2 (1) + 3 or 2 + 3 which gives us 5. Plugging a zero into the equation for x, we have 2 (0) + 3 which is just 0 + 3 or 3. Plugging in -1 into the equation for x, we have 2 (-1) + 3 which is -2 + 3 or 1.
I would always choose at least 3 values to plug into the equation for x. Notice that we now have 3 points that we can use to graph this equation. Our points are (1,5), (0,3), and (-1,1). Now, we can set up our coordinate system.
Image provided of the coordinate grid and table.
Notice the pattern that is shown with these points. They all lie on the same line. In fact, if we had chosen any other value to plug into the equation for x, that point would lie somewhere on that line. The graph of this equation is the line that contains these three points.