The number in the ones place= X
The number in the tenths place= y
y+x=14.
y=14-x
Original placement of numbers=10y+x
New placement of numbers(after subtraction of 36)= 10x+y
10y+ x-36=10x+y
Substitute y with 14-x
So we would get
10(14-x)+ x-36=10x+(14-x)
=140-10x+x-36=10x+14-x
After transposing we get
140-14-36=10x-x+10x-x
=90=18x
X=90/18
x=5
Y=14-x
=14-5
=9
So the two digit number is
10y+x
=90+5
=95
Answer:
Step-by-step explanation:
<u>Use of formula:</u>
- P(A and B) = P(A)*P(B|A) and
- P(A and B) = P(B)*P(A|B)
<u>According to above and based on given:</u>
- P(A)P(B|A) = P(B)P(A|B)
- P(B|A) = P(A|B)*P(B)/P(A)
- P(B|A) = 0.20*0.40/0.25 = 0.32
Answer:
Step-by-step explanation:
5, -4
5-4=1
5(-4)=-20
Answer:
2.92 × 10⁹
Step-by-step explanation:
im not exactly sure if im right but this is what i know, lmk if its wrong
