Answer:
The number of 32 Gigabit keys that can be fitted on the hard drive is 375.
Step-by-step explanation:
The question is:
If my hard drive has a capacity of 1.5 Terabytes, how many 32 Gigabit keys can fit on that hard drive?
Solution:
1 Terabyte = 8000 Gigabits
Then 1.5 Terabytes in Gigabits is:
1.5 Terabytes = (8000 × 1.5) Gigabits
= 12000 Gigabits
One key is of 32 Gigabits.
Compute the number of 32 Gigabit keys that can be fitted on the hard drive as follows:

Thus, the number of 32 Gigabit keys that can be fitted on the hard drive is 375.
It can be less than, more than or equal to zero
Answer:
You find if their less than or greater than
Step-by-step explanation:
when dividing or multiplying negative numbers switch sign.
Answer:
Option C.
Step-by-step explanation:
Note: The question and options are not in correct form.
Let the correct question is "Consider the formula for the average velocity, v, of a moving particle. In the formula, d1 and d2 represent the distance traveled by the particle at times t1 and t2 respectively.
v = (d2 - d1)/(t2 - t1)
Which of the following equations is equivalent to the formula for velocity?
A. t1=v(d2-d1)-t2
B. d1=v (t2-t1)-d2
C. d2=v(t2-t1)+d1
D. t2=v(d2-d1)+t1
"
The given formula is
On cross multiplication, we get
Add
on both sides.
Since,
, therefore, the correct option is C.