Question

Please help with this algebra problem!!

Answer 1

For one Fredburger, one Milk Shake and two order of Fries, we pay $4.34

Explanation:

Let us assume the cost of Fredburger as B, cost of Milk Shake as M, and cost of Order of Fries as Y.

As mentioned in the Question:

$B + M + Y = 3.72$ ----------- Equation 1

$B = M + 2 \times Y$, ----------- Equation 2

$3 \times M = B + Y$, ----------- Equation 3

Let us assume that we have to pay $X for one Fredburger, one Milk Shake and two order of Fries.

$B+M+2 \times Y = X$, consider this as Equation 4

Substituting Equation 3 into Equation 1:

$B + M + Y = 3.72$

$3 \times M + M = 3.72$

$4 \times M = 3.72$

$M = \frac{3.72}{4}$

M = $ 0.93

Substituting value of M in Equation 2,

$B = M + 2 \times Y\\\\B = 0.93 + 2 \times Y ------ Equation\ 5$

Substituting value of M in Equation 3,

$3 \times M = B + Y$

$3 \times 0.93 = B + Y$

$B + Y = 2.79$ ------------ Equation 6

Substituting Equation 5 in Equation 6,

$B + Y = 2.79 \\ \\ 0.93 + 2 \times Y + Y = 2.79$

$3 \times Y = 2.79 - 0.93$

$3 \times Y = 1.86$

$Y = \frac{1.86}{3}$

Y = $0.62

Substituting value of F in Equation 6,

$B + Y = 2.79$

$B + 0.62 = 2.79$

$B = 2.79 - 0.62$

B = $2.17

Substituting values of B, Y, and M in Equation 4,

$B+M+2 \times Y = X$

$2.17 + 0.93 +2 \times 0.62 = X$

$2.17 + 0.93 + 1.24 = X$

$X = $4.34