Can you be more specific.
1g= 0.001 kg
163000 * 0.001 = 163 kg
Answer:
y=81/10
Step-by-step explanation:
2/3y - 2/5 =5
lcm=15
(10y-6)/15=5
10y-6=75
10y=75+6
10y=81
y=81/10
Answer:
0.9113
Step-by-step explanation:
Given :
Sample standard deviation of Stock X = 4.665
Sample standard deviation of Stock Y = 8.427
Sample Covariance = 35.826
The Correlation Coefficient, R is related to sample covariance and standard deviation using the formular :
R = Covariance(X, Y) / (SD(X) * (SD(Y))
R = 35.826 / (4.665 * 8.427)
R = 35.826 / 39.311955
R = 0.9113
Hence, correlation Coefficient, R = 0.9113 which depicts a strong positive relationship.
Answer:
a) 0.3125 per hour
b) 2.225 hours
c) 8.9 hours
d) 12.1 hours
e) 80%
Step-by-step explanation:
Given that:
mean time = 3.2 hours, standard deviation (σ) = 2 hours
The mean service rate in jobs per hour (λ) = 2 jobs/ 8 hour = 0.25 job/hour
a) The average number of jobs waiting for service (μ)= 1/ mean time = 1/ 3.2 = 0.3125 per hour
b) The average time a job waits before the welder can begin working on it (L) is given by:

c) The average number of hours between when a job is received and when it is completed (Wq) is given as:

d) The average number of hours between when a job is received and when it is completed (W) is given as:

e) Percentage of the time is Gubser's welder busy (P) is given as:
