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NikAS [45]
4 years ago
8

Point W is on line segment VX. given VW=3 and VX=14, determine the length WX​

Mathematics
1 answer:
r-ruslan [8.4K]4 years ago
4 0

Answer:11

Step-by-step explanation:14-3=11

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which of the following gives an equation of a line that passes through the point (6 over 5, -19 over 5) and is parallel to the l
victus00 [196]
One equation for this would be

y = \frac{41}{16} x-\frac{55}{8}

We start by finding the slope between the two points:

m=\frac{y_2-y_1}{x_2-x_1}=\frac{-12-\frac{-19}{5}}{-2-\frac{6}{5}}
\\
\\=(-12+\frac{19}{5}) \div (-2-\frac{6}{5})
\\
\\=(\frac{-60}{5}+\frac{19}{5}) \div (\frac{-10}{5}-\frac{6}{5})
\\
\\=\frac{-41}{5} \div \frac{-16}{5}=\frac{-41}{5} \times \frac{-5}{16}=\frac{41}{16}

A line parallel to this one will have the same slope.  We will use point-slope form to write our equation:

y-y_1=m(x-x_1)
\\
\\y-\frac{-19}{5}=\frac{41}{16}(x-\frac{6}{5})
\\
\\y+\frac{19}{5}=\frac{41}{16}x- \frac{41}{16} \times \frac{6}{5}
\\
\\y+\frac{19}{5}=\frac{41}{16}x-\frac{246}{80}
\\
\\y+\frac{304}{80}=\frac{41}{16}x-\frac{246}{80}
\\
\\y=\frac{41}{16}x-\frac{246}{80}-\frac{304}{80}
\\
\\y=\frac{41}{16}x-\frac{550}{80}
\\
\\y=\frac{41}{16}x-\frac{55}{8}
6 0
3 years ago
Examine the following diagram:
Lisa [10]

Answer:

Its C: 41°

Step-by-step explanation:

it was right on edg :)

6 0
3 years ago
Read 2 more answers
Write an expression using exponents that is equivalent to 100,000
MrMuchimi
10^5 is equivalent to 100,000. I hope this answers your question and I hope you have a great day ! :)
6 0
3 years ago
Find the volume of a cone with a height of 3.25 centimeters and<br> a diameter of 2.2 centimeters.
saveliy_v [14]

Answer:

As per Provided Information

Height of cone h is 3.25 cm

Diameter of cone is 2.2 cm

  • Radius = Diameter/2

Radius = 2.2/2

Radius = 1.1 cm

We have been asked to determine the volume of the cone .

<u>Using </u><u>Formulae </u>

\boxed{\bf \:Volume_{(Cone)}  =  \cfrac{1}{3}  \pi {r}^{2}h}

Substituting the given value and let's solve it

\sf\longrightarrow \: Volume_{(Cone)}  =  \cfrac{1}{3}  \times 3.14 \times  {1.1}^{2}  \times 3.25 \\  \\  \\ \sf\longrightarrow \: Volume_{(Cone)}  =  \cfrac{1}{3}  \times 3.14 \times 1.21 \times 3.25 \\  \\  \\ \sf\longrightarrow \: Volume_{(Cone)}  =  \cfrac{1}{3}  \times 3.14 \times 3.9325 \\  \\  \\ \sf\longrightarrow \: Volume_{(Cone)}  =  \cfrac{1}{3}  \times 12.34805 \\  \\  \\ \sf\longrightarrow \: Volume_{(Cone)}  =  \cfrac{12.34805}{3}  \\  \\  \\ \sf\longrightarrow \: Volume_{(Cone)}  = 4.11 {cm}^{3}

<u>Therefore</u><u>,</u>

  • <u>Volume </u><u>of </u><u>the </u><u>cone </u><u>is </u><u>4</u><u>.</u><u>1</u><u>1</u><u> </u><u>cm³</u><u> </u><u>.</u>
3 0
2 years ago
How do you solve multiplying binomials with example: (x+4)^2
salantis [7]
This can be written as (x+4)(x+4)

Multiply everything in the second parenthesis by the x.

x^2 + 4x

Multiply everything in the second parenthesis by 4.

4x + 16

Add these two equations together.

x^2 + 4x + 4x + 16

Combine like terms.

x^2 + 8x + 16

Hope this helps!
8 0
3 years ago
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