3 years ago

X^2=20 square root property

1 answer:

4 0

${x}^{2} = 20 \\ x = \sqrt{20} \\ x = \sqrt{4} \times \sqrt{5} = 2 \times \sqrt{5} \\ \\ x = 2 \sqrt{5} \\ therefore \: \: x = 2\sqrt{5}$

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Full question...

To prove part of the triangle midsegment theorem using the diagram, which statement must be shown?

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