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4 years ago

How do you decide what operations are needed in a given situation?

1 answer:

4 0

If it says sum it is addition.When it says quotient it is division.When it says decrease it is subtraction.And when it says twice as Much it is multiplication

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The graph shows that f(x)={is translated<br> horizontally and vertically to get the function

yulyashka [42]

Answer: 3

Step-by-step explanation:

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3 years ago

Find the length of the third side to the nearest 10th

katovenus [111]

Answer:

9.5

Step-by-step explanation:

Using the pythagorean theorem a^2+b^2=c^2, we can say that 3^2+b^2=10^2.

Simplify and you get 9+b^2=100. Subtract 9 from both sides and you get b^2=91. When you take the square root you get 9.53939... round to the nearest tenth and the missing side is 9.5.

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3 years ago

Amelia went to an amusement park with $45 to spend. She bought lunch for 10.25 and paid $5.00 for each ride. What is the greates

garik1379 [7]

Answer:

Step-by-step explanation:

10.25 +5x6=40.25 if you add 5 for one more ride it is going to be 45.25 which is more

5 0

4 years ago

Help me pleaseeeeeeeeee!!

Step2247 [10]

[1,infinity sign) this is the answer

6 0

3 years ago

The annual net income of a company for the period 2007–2011 could be approximated by P(t) = 1.6t2 − 11t + 44 billion dollars (2

son4ous [18]

Answer:

$P'(t) = 3.2 t -11$

And we can set equal this derivate to 0 in order to find the critical point and we got:

$3.2 t-11= 0$

$t = \frac{11}{3.2}= 3.4375$

And we can calculate the second derivate and we got:

$P''(t) = 3.2 >0$

So then w can conclude that the value of t = 3.4375 represent the minimum value for the function and we can replace in the original function and we got:

$P(3.4375) = 1.6(3.4375)^2 - (11*3.4375) +44 = 25.094$

So then the minimum annual income occurs at t = 3.43 (between 2008 and 2009) and the value is 25.094

Step-by-step explanation:

For this case we have the following function:

$P(t) = 1.6 t^2 -11t +44$

Where P represent the annual net income for the period 2007-2011 and $2 \leq t \leq 7$

And t represent the time in years since the start of 2005

In order to find the lowet income we need to use the derivate, given by:

$P'(t) = 3.2 t -11$

And we can set equal this derivate to 0 in order to find the critical point and we got:

$3.2 t-11= 0$

$t = \frac{11}{3.2}= 3.4375$

And we can calculate the second derivate and we got:

$P''(t) = 3.2 >0$

So then w can conclude that the value of t = 3.4375 represent the minimum value for the function and we can replace in the original function and we got:

$P(3.4375) = 1.6(3.4375)^2 - (11*3.4375) +44 = 25.094$

So then the minimum annual income occurs at t = 3.43 (between 2008 and 2009) and the value is 25.094

5 0

3 years ago