Question

A blimp is 1300 meters high in the air and measures the angles of depression to two stadiums to the west of the blimp. If those measurements are 71.9° and 27.1°, how far apart are the two stadiums to the nearest meter?

Answer 1

Tanα=height/distance

tanα=h/d

d=h/tanα  so

d1=h/tanα  and d2=h/tanß

Then the distance between them is:

d=h/tanß-h/tanα, we know that h=1300, α=71.9°, and ß=27.1° so

d=3100/tan27.1-3100/tan71.9 meters

d≈5045 m (to nearest meter)

Answer 2

Answer:

Step-by-step explanation:

tanα=height/distance

tanα=h/d

d=h/tanα  so

d1=h/tanα  and d2=h/tanß

Then the distance between them is:

d=h/tanß-h/tanα, we know that h=1300, α=(90°-71.9°=18,1°), and ß=90°-27.1°=62.9°) so

d=(3100*tan62.9)-(3100*tan18.1) meters

d≈2116 (to nearest meter)