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AleksAgata [21]
3 years ago
12

A blimp is 1300 meters high in the air and measures the angles of depression to two stadiums to the west of the blimp. If those

measurements are 71.9° and 27.1°, how far apart are the two stadiums to the nearest meter?
Mathematics
2 answers:
kozerog [31]3 years ago
7 0
Tanα=height/distance

tanα=h/d

d=h/tanα  so

d1=h/tanα  and d2=h/tanß

Then the distance between them is:

d=h/tanß-h/tanα, we know that h=1300, α=71.9°, and ß=27.1° so

d=3100/tan27.1-3100/tan71.9 meters

d≈5045 m (to nearest meter)
Mademuasel [1]3 years ago
6 0

Answer:

Step-by-step explanation:

tanα=height/distance

tanα=h/d

d=h/tanα  so

d1=h/tanα  and d2=h/tanß

Then the distance between them is:

d=h/tanß-h/tanα, we know that h=1300, α=(90°-71.9°=18,1°), and ß=90°-27.1°=62.9°) so

d=(3100*tan62.9)-(3100*tan18.1) meters

d≈2116 (to nearest meter)

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bogdanovich [222]
We have y=ab^{x}

Plug in (0, 4):
4=ab^{0}⇒4=a
So we now have a

Plug in (3, 95):
95=4b^{3}
⇒b^{3}=\frac{95}{4}
⇒b=\sqrt[3]{\frac{95}{4}}
which is approximately 2.874

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y=4(\sqrt[3]{\frac{95}{4}})^{x}
or, in decimal form,
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7 0
3 years ago
an art teacher has 1 1/2 pounds of red clay and 3/4 pound of yellow clay.The teacher mixes the red clay and yellow clay together
Nataly [62]
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7 0
3 years ago
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The appropriate choice is ...
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A correct graph is shown below.

7 0
3 years ago
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3 0
3 years ago
The number of surface flaws in plastic panels used in the interior of automobiles has a Poisson distribution with a mean of 0.05
Tresset [83]

Answer:

(a) Probability that there are no surface flaws in an auto's interior is 0.6065 .

(b) If 10 cars are sold to a rental company, what is the probability that none of the 10 cars has any surface flaws is 0.00673 .

Step-by-step explanation:

We are given that the number of surface flaws in plastic panels used in the interior of automobiles has a Poisson distribution with a mean of 0.05 flaws per square foot of plastic panel.

Let X = Distribution of number of surface flaws in plastic panels

So, X ~ Poisson(\lambda)

The mean of Poisson distribution is given by, E(X) = \lambda = 0.05

which means, X ~ Poisson(0.05)

The probability distribution function of a Poisson random variable is:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!}; for  x=0,1,2,3...

Now, we know that \lambda for per square foot of plastic panel is 0.05 and we are given that an automobile interior contains 10 square feet of plastic panel.

Therefore,  for 10 square foot of plastic panel is = 10 * 0.05 = 0.5

(a) Probability that there are no surface flaws in an auto's interior =P(X=0)

    P(X = 0) = \frac{e^{-0.5}*0.5^{0}}{0!} = e^{-0.5} = 0.6065

(b) If 10 cars are sold to a rental company, what is the probability that none of the 10 cars has any surface flaws = P(X = 0)^{10}

    So, P(X = 0)^{10} = 0.6065^{10} = 0.00673

8 0
3 years ago
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