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Tanzania [10]
4 years ago
15

You are filling a 5-L fish tank using a 259-ml container. How many full containers are required to fill the fish tank?

Mathematics
2 answers:
Lubov Fominskaja [6]4 years ago
5 0
5L=5000 ml
5000ml:259 ml≈ 84.74
That means 84 full containers.
slega [8]4 years ago
4 0
It would take 19.31 full containers to fill the fish tank.
There is 1000 ml in a L making it 5000 ml needed to fill the tank.
Divide the 5000 ml by 259 ml to get your answer.
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PLZ HELP
Roman55 [17]
She has 65 water bottles....and she is buying boxes of water bottles (x) that hold 16 water bottles each. She can only buy up to 5 water bottles.

f(x) = 16x + 65...where f(x) = total water bottles and x = number of boxes
x < = 5.....here is ur restriction

the range is ur f(x) values which represent the total number of water bottles...keep in mind, she can only buy 5. Therefore, the numbers that can be subbing in for x are 0 thru 5.

So when subbing in 0 thru 5 for x, the results for f(x) are :
{ 65,81,97,113,129 } <== ur range
4 0
4 years ago
At Chester’s Bakery, a box of 12 donuts sells for $8.50. What is the unit price of the donuts in the box, rounded to the nearest
sergiy2304 [10]
You would take 8.50 and divide it by 12.
to get $0.71
7 0
4 years ago
Attached as picture. Please read fully
Troyanec [42]

a. The velocity t = v = Ce_{n} (\frac{mo}{mo - kt} ) - gt

b. v60 = 7164

<h3>How to solve for the velocity</h3>

mdv/dt = ck - mg

dv/dt = ck/m - mg/m

= ck/m - g

dv = (\frac{ck}{Mo-Kt} -g)dv

Integrate the two sides of the equation to get

v -\frac{ck}{k} e_{n} (Mo- kt)-gt+c

v = Ce_{n} (\frac{mo}{mo - kt} ) - gt

b. fuel accounts for 55% of the mass

So final mass after fuel is burned out is = 0.45

c=2500

g=9.8

t=60

v = -2500ln0.45 - 9.8 x 60

= 7752 - 588

= 7164

<h3>Complete question</h3>

A rocket, fired from rest at time t = 0, has an initial mass of m0 (including its fuel). Assuming that the fuel is consumed at a constant rate k, the mass m of the rocket, while fuel is being burned, will be given by m0 - kt. It can be shown that if air resistance is neglected and the fuel gases are expelled at a constant speed c relative to the rocket, then the velocity of the rocket will satisfy the equation where g is the acceleration due to gravity.

dv dt m =ck - mg

(a) Find v(t) keeping in mind that the mass m is a function of t.

v(t) =

m/sec

(b) Suppose that the fuel accounts for 55% of the initial mass of the rocket and that all of the fuel is consumed at 60 s. Find the velocity of the rocket in meters per second at the instant the fuel is exhausted. [Note: Take g = 9.8 m/s² and c = 2500 m/s.]

v(60) =

m/sec [Round to nearest whole number]

Raed more on velocity here

brainly.com/question/25749514

#SPJ1

8 0
2 years ago
What is 3456 x 3 hundreds
alekssr [168]

Answer:

3456 × 300 is equal to <u>1</u><u>0</u><u>3</u><u>6</u><u>8</u><u>0</u><u>0</u><u>.</u>

4 0
3 years ago
Read 2 more answers
7. The simplest radical form of 2(5V6 - 724) is<br> A 2V3<br> B 1073-62<br> C 6V3<br> D 1073-2V6
Irina-Kira [14]

Answer: the real answer for this is 10v6-1448

Step-by-step explanation: here

2(5v6-724)

=(2)(5v6)+(2)(-724)

=10v6-1448

6 0
3 years ago
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