She has 65 water bottles....and she is buying boxes of water bottles (x) that hold 16 water bottles each. She can only buy up to 5 water bottles.
f(x) = 16x + 65...where f(x) = total water bottles and x = number of boxes
x < = 5.....here is ur restriction
the range is ur f(x) values which represent the total number of water bottles...keep in mind, she can only buy 5. Therefore, the numbers that can be subbing in for x are 0 thru 5.
So when subbing in 0 thru 5 for x, the results for f(x) are :
{ 65,81,97,113,129 } <== ur range
You would take 8.50 and divide it by 12.
to get $0.71
a. The velocity t = 
b. v60 = 7164
<h3>How to solve for the velocity</h3>
mdv/dt = ck - mg
dv/dt = ck/m - mg/m
= ck/m - g
dv = 
Integrate the two sides of the equation to get
v 

b. fuel accounts for 55% of the mass
So final mass after fuel is burned out is = 0.45
c=2500
g=9.8
t=60
v = -2500ln0.45 - 9.8 x 60
= 7752 - 588
= 7164
<h3>Complete question</h3>
A rocket, fired from rest at time t = 0, has an initial mass of m0 (including its fuel). Assuming that the fuel is consumed at a constant rate k, the mass m of the rocket, while fuel is being burned, will be given by m0 - kt. It can be shown that if air resistance is neglected and the fuel gases are expelled at a constant speed c relative to the rocket, then the velocity of the rocket will satisfy the equation where g is the acceleration due to gravity.
dv dt m =ck - mg
(a) Find v(t) keeping in mind that the mass m is a function of t.
v(t) =
m/sec
(b) Suppose that the fuel accounts for 55% of the initial mass of the rocket and that all of the fuel is consumed at 60 s. Find the velocity of the rocket in meters per second at the instant the fuel is exhausted. [Note: Take g = 9.8 m/s² and c = 2500 m/s.]
v(60) =
m/sec [Round to nearest whole number]
Raed more on velocity here
brainly.com/question/25749514
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Answer:
3456 × 300 is equal to <u>1</u><u>0</u><u>3</u><u>6</u><u>8</u><u>0</u><u>0</u><u>.</u>
Answer: the real answer for this is 10v6-1448
Step-by-step explanation: here
2(5v6-724)
=(2)(5v6)+(2)(-724)
=10v6-1448