Answer:
In 1981, the Australian humpback whale population was 350
Po = Initial population = 350
rate of increase = 14% annually
P(t) = Po*(1.14)^t
P(t) = 350*(1.14)^t
Where
t = number of years that have passed since 1981
Year 2000
2000 - 1981 = 19 years
P(19) = 350*(1.14)^19
P(19) = 350*12.055
P(19) = 4219.49
P(19) ≈ 4219
Year 2018
2018 - 1981 = 37 years
P(37) = 350*(1.14)^37
P(37) = 350*127.4909
P(37) = 44621.84
P(37) ≈ 44622
There would be about 44622 humpback whales in the year 2018
Answer:
Step-by-step explanation:
56y^2/9-30y+25
Answer:
$1.80 + (8x$0.10)*4.5 = $5.40
Step-by-step explanation:
$1.80 base cost
$0.10 for an 8th of a mile, thus multiply by 8 = $0.80 per mile
So, $1.80 + (4.5 * $0.8) = $5.40
<u>Hint </u><u>:</u><u>-</u>
- To find out the equation of the line we can use the point slope form of the line which is
<u>Solution</u><u> </u><u>:</u><u>-</u>
The given point to us is , 
and the slope of the line is 4 . On using the point slope form , we have ,
<u>Hence</u><u> the</u><u> </u><u>equation</u><u> </u><u>is </u><u>4</u><u>x</u><u> </u><u>-</u><u> </u><u>y </u><u>+</u><u> </u><u>3</u><u> </u><u>=</u><u> </u><u>0</u><u> </u>
( for graph , see attachment ) .
The answer is A) Dilation, because a dilation makes an object bigger or smaller. hope this helped :D
