1.)
Between year 0 and year 1, we went from $50 to $55.
$55/$50 = 1.1
The price increased by 10% from year 0 to year 1.
Between year 2 and year 1, we went from $55 to $60.50.
$60.50/$55 = 1.1
The price also increased by 10% from year 1 to year 2. If we investigate this for each year, we will see that the price increases consistently by 10% every year.
The sequence can be written as an = 50·(1.1)ⁿ
2.) To determine the price in year 6, we can use the sequence formula we established already.
a6 = 50·(1.1)⁶ = $88.58
The price of the tickets in year 6 will be $88.58.
Answer:
The greatest number of bracelets she can buy is 63.
Step-by-step explanation:
12 + 0.60x ≤ 50
- Since we already have the inequality, we have to start picking random numbers(until there are no more solutions):
1.) 12 + 0.60(63) ≤ 50
12 + 37.8 ≤ 50
49.8 ≤ 50
Since 49.8 ≤ 50 is always true, there are infinitely many solutions.
- Now we know that she can buy 63 bracelets, we have to figure out if she can buy more:
2.) 12 + 0.60(64) ≤ 50
12 + 38.4 ≤ 50
50.4 ≤ 50
Since 50.4 ≤ 50 is false, there is no solution.
How about u go to first grade not k anything and cheating matter the fact I’m calling it mom
Answer:
200 degrees.
Step-by-step explanation:
By theorem of inscribed angle...
The measure of an inscribed angle is half the measure of the intercepted arc. [Theorem]
therefore, m(angle J) = half of m(arc CDE)
therefore, m(arc CDE) = 2 * m(angle J)
therefore, m(arc CDE) = 2 ( 100)
therefore, m(arc CDE) = 200 degrees.
Answer:
C is your answer
Step-by-step explanation: