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skelet666 [1.2K]
4 years ago
13

How do i evaluate this problem ?

Mathematics
1 answer:
Charra [1.4K]4 years ago
8 0

plug a=2 and b=4 in the expression

5(2)+7(4)

simplify

10+28

solve

=38

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29x+2=31<br> Giving brainliest if do correct..<br> Explanation also or reported
olasank [31]

Answer:

x = 1

Step-by-step explanation:

29x + 2 = 31

       -2      -2

29x = 29

-----    -----

29      29

x = 1

8 0
3 years ago
On 1 st March, 2020 Mr. Mohit started a Furniture business in GANDHI NAGAR Mr. Mohit invested Rs 50,00,000.
d1i1m1o1n [39]

Answer:

Answer to the following question is as follows;

Step-by-step explanation:

Given:

Amount invested by Mr. Mohit = Rs. 50,00,000

Computation:

Books of (...... LTD)

Journal entries

Date                         Particular                        Debit        Credit

March 1         Cash                     A/C Dr.     50,00,000

                     To Capital            A/C Cr.                         50,00,000

(Being Amount invested in new business)

8 0
3 years ago
Elizabeth has $680 to spend at a bicycle store for some new gear and biking outfits.
Mama L [17]

Answer: 5 outfits

Step-by-step explanation: 17.63x2=35.26

                                             437.63+35.26+18.11=491

                                              680-491=189

                                              189 divided by 35.19= 5 (rounded)

4 0
3 years ago
S2 Summer Holiday Homework
Juli2301 [7.4K]

 

I. xy + 2y=3       Not linear equation because is grade 2 equation  (xy).

II. x-2y = y              Are linear equations in two unknowns  (x and y).

III. 3x + 2y = 5      Are linear equations in two unknowns  (x and y).

<h2>Corect ansver:    C)  II and III only</h2><h2></h2>

.

6 0
4 years ago
1)X²+5X-50=0<br>2)6²+6B-16=0<br>3)R²+6R+8=0<br>4)P²+5P+6=0​
zubka84 [21]

1) X²+5X-50=0

↠X² + 10X -5X -50 = 0

↠X(X+10)-5(X+10) = 0

↠(X-5)(X+10)=0

↠X = 5, -10

2)B²+6B-16=0

↠B² + 8B - 2B -16 = 0

↠B(B+8) -2(B+8) =0

↠(B-2) (B+8) =0

↠B = 2,-8

3)R²+6R+8=0

↠R²+4R+2R+8=0

↠R(R+4)+2(R+4)=0

↠(R+2)(R+4)=0

↠R=-2,-4

4) P²+5P+6=0

↠P²+3P+2P+6=0

↠P(P+3)+2(P+3)=0

↠(P+2)(P+3)=0

↠P=-2,-3

6 0
2 years ago
Read 2 more answers
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