omar jogged a total of 3 3/5 miles last week. Each day that he jogged,he went 9/10 mile. On how many days did he jog?
2 answers:
Answer:
4 days
Step-by-step explanation:
Given :Omar jogged a total of miles last week.
Each day that he jogged,he went mile.
To Find : On how many days did he jog?
Solution :
He went for miles in 1 day =
Let x be the no. of days he jogged.
He went for miles in x day =
We are given that Omar jogged a total of miles last week.
So,
Hence He did jog for 4 days .
You might be interested in
Answer:
Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.
Step-by-step explanation:
We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.
So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;
Z = ~ N(0,1)
where, = average age of the random sample of horses with colic = 12 yrs
= average age of all horses seen at the veterinary clinic = 10 yrs
= standard deviation of all horses coming to the veterinary clinic = 8 yrs
n = sample of horses = 60
So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P(
12)
P(
12) = P(
) = P(Z
1.94) = 1 - P(Z < 1.94)
= 1 - 0.97381 = 0.0262
Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.