Answer:
fx(x)=[(4! /(x!)*(4-x)!]*[(0.3) ^x]*[(0.7) ^ (4-x)]
Step-by-step explanation:
F(x) is been calculated by considering X (moderate) as one outcome and low and high combined as one outcome now probability function will be same as binomial distribution
F(x) = [(4! /(x!)*(4-x)!]*[(0.3) ^x]*[(0.7) ^ (4-x)]
Answer:
7) 49°
8) 77°
9) 87°
10) 135°
Step-by-step explanation:
7) The angles are between the parallel lines, so are "interior." They are on opposite sides of the transversal, so are "opposite interior" angles. Such angles are congruent, so ...
... ? ≅ 49°
8) The angles are adjacent interior angles, so are supplementary.
... ? + 103° = 180°
... ? = 77°
9) The angles are outside the parallel lines, so are "exterior." They are on opposite sides of the transversal, so are "opposite exterior" angles. Such angles are congruent.
... ? ≅ 87°
10) These are vertical angles, so are congruent. (The other parallel line is irrelevant and doesn't need to be there for this relationship to be true.)
... ? ≅ 135°
The formula of the volume of the rectangular prism:
V = length × width × height
We have:
Answer:
x =60 ° angles on a straight line
y+25° =120° exterior angle of the triangle
y=120°-25°=95°
y =95 °
Answer:
b(b/a)^2
Step-by-step explanation:
Given that the value of the car depreciates such that its value at the end of each year is p % less than its value at the end of the previous year and that car was worth a dollars on December 31, 2010 and was worth b dollars on December 31, 2011, then
b = a - (p% × a) = a(1-p%)
b/a = 1 - p%
p% = 1 - b/a = (a-b)/a
Let the worth of the car on December 31, 2012 be c
then
c = b - (b × p%) = b(1-p%)
Let the worth of the car on December 31, 2013 be d
then
d = c - (c × p%)
d = c(1-p%)
d = b(1-p%)(1-p%)
d = b(1-p%)^2
d = b(1- (a-b)/a)^2
d = b((a-a+b)/a)^2
d = b(b/a)^2 = b^3/a^2
The car's worth on December 31, 2013 = b(b/a)^2 = b^3/a^2
